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Zepler [3.9K]
4 years ago
5

PLEASE HELP I WILL RATE YOU BRAINLIEST!!

Mathematics
1 answer:
DerKrebs [107]4 years ago
5 0
-5.8 = -5 \frac{8}{10} = -5 \frac{4}{5}
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Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is g
Soloha48 [4]

Answer:

The equation for difference in altitude of the two helicopters is A =  650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is,  A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁  = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁  = A =  1250 + 50t - 600 -150t

A₂ - A₁  = A = 1250 - 600 + 50t - 150t

A₂ - A₁  = A =  650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A =  650 - 100t

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  • Opposite side to <WYX=WX
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As

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