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Sergio039 [100]
3 years ago
5

Evaluate the given equation for the indicated function values. pls help

Mathematics
1 answer:
Xelga [282]3 years ago
8 0

Answer:

The answer in each numeral is:

  1. <u>f(4) = 28</u>
  2. <u>f(10) = -19</u>
  3. <u>f(-5) = -33</u>
  4. <u>f(9) = -9</u>

Step-by-step explanation:

To obtain the result in each case, you must replace the variable (n) by the value that appears in the second case, I'll explain it with the first exercise:

  • 1. f(n) = 5n + 8
  •   f(4) = ?

As you can see, in the second doesn't appear f(n), but f(4), that means you must replace the "n" in the equation by 4, if we do this, we obtain:

  • 1. f(4) = 5*(4) + 8
  • f(4) = 20 + 8
  • <u>f(4) = 28</u>

The first answer is 28, now we'll continue with the next exercises:

  • 2. f(n) = -2n + 1
  • f(10) = -2*(10) + 1
  • f(10) = -20 + 1
  • <u>f(10) = -19</u>

  • 3. f(n) = 6n - 3
  • f(-5) = 6*(-5) - 3
  • f(-5) = -30 - 3
  • <u>f(-5) = -33</u>

  • 4. f(n) = -n
  • <u>f(9) = -9</u>

In this form, <u><em>you can prove the answers are: 28, -19, -33, and -9 respectively</em></u>.

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
The percentage 21 is of 28 is equal to the percentage 30 is of 40<br> True?<br> or false?
katovenus [111]

Answer:

False

Step-by-step explanation:

75%

21

28 5.88

21 x 28

100

= 5.88

x 100% = 75%33.3333333333%

28 - 21

21

x 100% = 33.3333333333%

5 0
3 years ago
Help!!!!! with this please
stealth61 [152]

Answer:

y+mx+b

Step-by-step explanation:

4 0
3 years ago
Please answer<br><br> Quickly
Mashcka [7]
The answer is 21

By comparing the 4 vertices you can determine the rectangle x-length and y-length. The coordinate for the vertice is:
1,+4i
-2, +4i
-2, -3i
1, -3i

From the coordinate, you can see there are 2 x coordinate(1 and -2) and 2 y coordinate(4i and -3i) that used.
The x-length would be: 1 - (-2)= 3
The y-length would be: 4i- (-3i)= 7i

Then the area of the rectangle would be:
area= x-length * y-length= 3*7=21
8 0
3 years ago
I really need help!!!
Ksenya-84 [330]

Answer(-2:23)


Step-by-step explanation:gose in a pattern.


8 0
3 years ago
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