Question

in order to prepare 60g of 10% sodium carbonate solutions, how many grams of water and sodium carbonate is needed

Answer 1

Answer:

The mass of water = 54 g

Mass of sodium carbonate = 6 g

Explanation:

• To calculate the mass  needed when given the volume of water and percentage mass we can use the formula;

$Mass of sodium carbonate = \frac{(Volume of water)(percentage mass)}{(100-percentage mass)}$

In this case;

Percentage mass = 10 %

Total mass of solution = 60 g

Assuming the volume of water = y cm³, the mass of water is y g

Then, the mass of sodium carbonate(solute)= 60-y

Hence;

$60-y = \frac{10y}{(100-10)}$

$90(60-y) = 10y\\5400-90y =10y\\5400 = 100 y\\y =54$

Therefore;

The mass of water = 54 g

Mass of sodium carbonate = 6 g