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Shalnov [3]
3 years ago
12

A chemist adds of a mercury(I) chloride solution to a reaction flask. Calculate the micromoles of mercury(I) chloride the chemis

t has added to the flask.
Chemistry
1 answer:
Georgia [21]3 years ago
7 0

Answer:

3.383x10⁻³ micromoles of HgCl

Explanation:

<em>The chemist adds 170mL of a 1.99x10⁻⁵mmol/L Mercury (I) chloride, HgCl.</em>

<em />

The solution contains 1.99x10⁻⁵milimoles of HgCl in 1L. That means in 170mL = 0.170L there are:

0.170L × (1.99x10⁻⁵milimoles HgCl / L) = 3.383x10⁻⁶ milimoles of HgCl.

Now, in 1milimole you have 1000 micromoles. That means in 3.383x10⁻⁶ milimoles of HgCl you have:

3.383x10⁻⁶ milimoles of HgCl ₓ (1000micromoles / 1milimole) =

<h3>3.383x10⁻³ micromoles of HgCl</h3>
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The solid anhydrous solid CoCl2 is blue in color. Because it readily absorbs water from the air, it is used as a humidity indica
MrRissso [65]

Answer:

CoCl_{2}.(H_{2}O)_{6} is formed and it has three unpaired electrons.

Explanation:

Blue CoCl_{2} reacts with water to produce pink colored CoCl_{2}.(H_{2}O)_{6} complex.

In this complex, Co^{2+} ion forms an octahedral complex with six H_{2}O ligands.

As H_{2}O is a weak field ligand therefore Co^{2+} ion remains in low spin state.

Hence electronic configuration of Co^{2+} ion in this octahedral geometry is t_{2g}^{5}e_{g}^{2} with total three unpaired electrons.

6 0
3 years ago
A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio
MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass  / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758  grams

Thus, the percent yield for this reaction = \frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100

or

the percent yield for this reaction = \frac{0.53}{0.5758}\times100

or

the percent yield for this reaction = 92.04%

6 0
3 years ago
Determine the empirical formula for a compound that contains 15.8% carbon and 84.2% sulfer
nydimaria [60]

Answer:

Carbon Disulfide CS2

Explanation:

6 0
3 years ago
Write the equilibrium expression of each chemical equation.<br> 2H2S(g) 2H2(g) + S2(g)
hodyreva [135]

Answer:

<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u>

Explanation:

2H2S(g)⇋2H2(g)+S2(g)2H2S(g)⇋2H2(g)+S2(g)

The equilibrium constant expression in terms of concentrations is:

Kc=<u>[H2]2[S2][H2S]2Kc=[H2]2[S2][H2S]2</u><u>.</u>

6 0
3 years ago
If a person had the values for an objects density and volume, what value can be calculated
zavuch27 [327]

Hello there! With the values of density and volume, you would be able to find the object's mass.

Density is found by dividing the mass by the volume, so you could place in the values of the density and the volume to get the mass.

For example:

500 = mass/10

The 500 being density and 100 being volume. You would use simple math rules and multiply 10 by 500, and you'd get 5000, therefore using the density and volume values and giving you the mass.

I hope I could help you and have a great day!

5 0
3 years ago
Read 2 more answers
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