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Shalnov [3]
2 years ago
12

A chemist adds of a mercury(I) chloride solution to a reaction flask. Calculate the micromoles of mercury(I) chloride the chemis

t has added to the flask.
Chemistry
1 answer:
Georgia [21]2 years ago
7 0

Answer:

3.383x10⁻³ micromoles of HgCl

Explanation:

<em>The chemist adds 170mL of a 1.99x10⁻⁵mmol/L Mercury (I) chloride, HgCl.</em>

<em />

The solution contains 1.99x10⁻⁵milimoles of HgCl in 1L. That means in 170mL = 0.170L there are:

0.170L × (1.99x10⁻⁵milimoles HgCl / L) = 3.383x10⁻⁶ milimoles of HgCl.

Now, in 1milimole you have 1000 micromoles. That means in 3.383x10⁻⁶ milimoles of HgCl you have:

3.383x10⁻⁶ milimoles of HgCl ₓ (1000micromoles / 1milimole) =

<h3>3.383x10⁻³ micromoles of HgCl</h3>
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