I would think that all but one point would be on the line. One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation. Next time, would you please enclose the coordinates of each point inside parentheses: (2.5,14), (2.25,12), and so on, to avoid confusion.
14-12
slope of line thru 1st 2 points is m = ---------------- = 2/0.25 = 8
2.50-2.25
What is the eqn of the line: y = mx + b becomes
14 = (8)(2.5) + b; find b:
14-20 = b = -6. Then, y = 8x - 6.
Now determine whether (12,1.25) lies on this line.
Is 1.25 = 8(12) - 6? Is 1.25 = 90? No. So, unless I've made arithmetic mistakes, (1.25, 5) does not lie on the line thru (2.5,14) and (2.25,12).
Why not work this problem out yourself using my approach as a guide?
The next term in the sequence will be increased by 27.
The difference between 15 and 34 is 19
The difference between 34 and 55 is 21
The difference between 55 and 78 is 23
The difference between 78 and 103 is 25
Following this pattern, the next number will be 130
Given:
The function is:

To find:
The inverse of the given function, then draw the graphs of function and its inverse.
Solution:
We have,

Step 1: Substitute
.

Step 2: Interchange x and y.

Step 3: Isolate variable y.


Step 4: Substitute
.

Therefore, the inverse of the given function is
and the graphs of these functions are shown below.
At high noon, you can feel warm
air coming from inland. During noon, especially in spring and summer, the
radiation caused by the Sun warms the land surface more compared to the sea
surface. This is because heat is directly applied on the land surface compared
to the ocean.
Answer:

Step-by-step explanation:
step 1
Find the 
we know that
Applying the trigonometric identity

we have

substitute





Remember that
π≤θ≤3π/2
so
Angle θ belong to the III Quadrant
That means ----> The sin(θ) is negative

step 2
Find the sec(β)
Applying the trigonometric identity

we have

substitute




we know
0≤β≤π/2 ----> II Quadrant
so
sec(β), sin(β) and cos(β) are positive

Remember that

therefore

step 3
Find the sin(β)
we know that

we have


substitute

therefore

step 4
Find sin(θ+β)
we know that

so
In this problem

we have




substitute the given values in the formula


