Add up 3+3=6, number has to be bigger than 9 so the answer is false.
Step-by-step explanation:
solution:- from LHS 1-cos²x/sinx
∵ 1-cos²x = sin²x
∴ sin²x /sinx = sinx
from RHS tanx × cosx
∵tanx = sinx×cosx
∴ sinx/ cosx × cosx = sinx
Since, LHS = RHS proved ___
Answer:
1. 121 π unit²
2. 143°
3. 151 unit²
Step-by-step explanation:
1.
Area of a circle is given by the formula A = πr²
where
A is the area,
r is the radius of the circle
From the given diagram, we can see that the radius is 11, hence the area will be:
![A=\pi r^2\\A=\pi (11)^2\\A=121\pi](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%5C%5CA%3D%5Cpi%20%2811%29%5E2%5C%5CA%3D121%5Cpi)
The answer is
units^2
2.
The unshaded secctor and the shaded sector equals the circle. We know that circle is 360°. The unshaded sector has an angle of 217°. So the shaded part will be 360 - 217 = 143°
The measure of the central angle of the shaded sector is 143°
3.
Area of a sector is given by the formula ![A=\frac{\theta}{360}*\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Ctheta%7D%7B360%7D%2A%5Cpi%20r%5E2)
Where
is the central angle of the sector (in our case it is 143°)
r is the radius (which is 11)
Plugging in all the info into the formula we have:
![A=\frac{\theta}{360}*\pi r^2\\A=\frac{143}{360}*\pi (11)^2\\A=150.99](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Ctheta%7D%7B360%7D%2A%5Cpi%20r%5E2%5C%5CA%3D%5Cfrac%7B143%7D%7B360%7D%2A%5Cpi%20%2811%29%5E2%5C%5CA%3D150.99)
<em>rounding to the nearest whole number, it is </em>151 units^2
Hey! Glad I can help!!!
0.4 is the tenth in there.
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Answer: see below
<u>Step-by-step explanation:</u>
Write each equation in y = mx + b format where m is the slope and b is the y-intercept.
Left side: -4 ≤ x < -1
If you continue the line through the y-axis it will pass through (0, 4) --> b = 4
The rise over run is -1 over 1 --> m = -1
y = (-1)x + (4) --> y = -x + 4
Right side: -1 < x < 4
The line passes through (0,0) --> b = 0.
The rise over run is -1 over 1 --> m = -1
y = (-1)x + (0) --> y = -x
![\large\boxed{f(x)=\bigg\{\begin{array}{ll} -x+4&;-4\leq x](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bf%28x%29%3D%5Cbigg%5C%7B%5Cbegin%7Barray%7D%7Bll%7D%20-x%2B4%26%3B-4%5Cleq%20x%3C-1%5C%5C%20-x%26%3B-1%3Cx%3C4%20%5Cend%7Barray%7D%7D)