Answer:
![\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20g%5E%7B-1%7D%28x%29%3D%5Csqrt%7B%5Cdfrac%7Bx%2B5%7D%7B3%7D%7D%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello,
![x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\3(g^{-1}(x))^2 = x+5\\\\\\ (g^{-1}(x))^2=\dfrac{x+5}{3}\\g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}](https://tex.z-dn.net/?f=x%3D%28gog%5E%7B-1%7D%29%28x%29%3Dg%28g%5E%7B-1%7D%28x%29%29%3D3%28g%5E%7B-1%7D%28x%29%29%5E2-5%5C%5C%5C%5C%3C%3D%3E3%28g%5E%7B-1%7D%28x%29%29%5E2%20%3D%20x%2B5%5C%5C%5C%5C%5C%5C%3C%3D%3E%20%28g%5E%7B-1%7D%28x%29%29%5E2%3D%5Cdfrac%7Bx%2B5%7D%7B3%7D%5C%5C%3C%3D%3Eg%5E%7B-1%7D%28x%29%3D%5Csqrt%7B%5Cdfrac%7Bx%2B5%7D%7B3%7D%7D)
hope this helps
16.5+4.73= 21.23 it’s basically regular adding just with decimal
6x+2y factor out 2
2(3x+y)
...
We were told that 3x+y=6 so
2(3x+y)=2(6)
6x+2y=12
No, because 2/5 is .4 and 4/12 is 1/3 or .333
So Jed is much faster than Alex in free throws.