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3 years ago

Solve the system of linear equations in two variables by elimination or substitution.

Mathematics

1 answer:

8090 [49]3 years ago

5 0

Answer:

x = 0.8 y = 0.6

Step-by-step explanation:

Solve one of the equations for a single variable, I chose the 2nd equation and solved for the variable y and I got y = 2x -1.

Next plug in the value for y into the 1st equation, I got :

2x + 4 ( 2x - 1) = 4

Next solve for x by first distributing the 4 to the (2x-1), this becomes (8x -4) then add like terms and move the -4 to the other side of the equation by addition. I got 10x =8 then I divided 8/10 to solve for x and I got 0.8.

Now plug the value 0.8 in for x in the 2nd equation : 2*(0.8) - y = 1

Then solve for y by subtracting 2*(0.8) or 1.6 from 1 and I got -0.6, lastly divide by -1 to solve for y.

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Answer:

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Step-by-step explanation:

Given

See attachment

Required

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Because the bottom part of the upper piece is not visible, the area is calculated as:

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3 years ago

Evaluate the expression<br><br> x^2 (y - 2)<br> —————, if x=3, and y= -1<br> 3y

vitfil [10]

Answer:

$\huge\boxed{\sf 9}$

Step-by-step explanation:

$\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

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