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ohaa [14]
3 years ago
10

Wanda starts with $1200 and deposits $40 per week. Zelda starts with $700 and deposits $50 per week. When will Wanda have the sa

me amount of money as Zelda
Mathematics
1 answer:
Masja [62]3 years ago
4 0
Let the number of weeks to have same amount = x Then:-

1200 + 40x = 700 + 50x
1200 - 700 = 50x - 40x

10x =  500
x = 50  
answer is 50 weeks
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Which of the following represents "five times the sum of a number and fifteen is fifty"?
Kisachek [45]
Yes, the correct answer is A because you're multiplying 5 by the expression (N+15)
6 0
3 years ago
Read 2 more answers
5 Consider this system of equations:<br> 5x + y = -2<br> 2x - 2y=4
Ilia_Sergeevich [38]

Answer:

x  = 0

  y  = -2

Step-by-step explanation:

The given system of equation are:

   5x + y = -2

   2x - 2y = 4  

The problem here is to find x and y from the expression

   5x + y = -2     ----- i

   2x - 2y = 4    ---- ii

 So;

i x 2 :  10x + 2y  = -4     ----  iii

ii x 5 :  10x - 10y  = 20    ----- iv

   iii - iv;   12y  = -24

                  y  = -2

    Now find x;

             5x + y  = -2

             5x  - 2  = -2

                  x  = 0

 

7 0
3 years ago
What is the simplified form of the quantity y−squared minus y minus 12 over the quantity y−squared minus 2y minus 15?
makvit [3.9K]
(y^2-y-12)/(y^2-2y-15)  factor both the numerator and denominator...

(y^2-4y+3y-12)/(y^2-5y+3y-15)

(y(y-4)+3(y-4))/(y(y-5)+3(y-5))

((y-4)(y+3))/((y-5)(y+3))  so the (y+3) terms cancel leaving

(y-4)/(y-5)

6 0
3 years ago
Suppose that $1200 is invested at 612%, compounded quarterly. How much is in the account at the end of 5 years?
asambeis [7]

Answer:

\$1,656.50  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=5\ years\\ P=\$1,200\\ r=6\frac{1}{2}\%=6.5\%=6.5/100=0.065\\n=4  

substitute in the formula above

A=1,200(1+\frac{0.065}{4})^{4*5}  

A=1,200(1.01625)^{20}  

A=\$1,656.50  

5 0
3 years ago
25c - 5 factored form
Lorico [155]
5(5c-1)

Hope this helps!
7 0
4 years ago
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