Answer:
what on the planet is the question
Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so

In this problem we have

substitute



therefore
Polygon q’s area is one fourth of polygon p’s area
Answer:
60
Step-by-step explanation:
Looking at case 1.
a * 10^5 + 2a * 10 ^4= 7200000
a * 10 * 10^4 + 2a *10 ^4 =7200000
[10a + 2a] * 10^4= 7200000
12a= 7200000/ 10000
12a= 720
a= 720/12 = 60
Looking at case 2,
a * 10^5 - a * 10^4 = 5400000
a * 10 * 10^4 - a *10^4 = 5400000
10a* 10^ 4 - a * 10^ 4 = 5400000
[10a- a] *10^4 = 5400000
9a = 5400000/10000
9a= 540
a =540/9
a= 60
Answer:
(2x - 3)(x + 2)
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(
+ x) - 6
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring
+x-6
The first term is,
its coefficient is 2 .
The middle term is, +x its coefficient is 1 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 2 • -6 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is 1 .
-12 + 1 = -11
-6 + 2 = -4
-4 + 3 = -1
-3 + 4 = 1 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 4
- 3x + 4x - 6
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-3)
Add up the last 2 terms, pulling out common factors :
2 • (2x-3)
Step-5 : Add up the four terms of step 4 :
(x+2) • (2x-3)
Which is the desired factorization
(2x - 3)(x + 2)
Answer: A.
= 2
= 9
Step-by-step explanation:
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