Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
I feel like everyone is entitled to their own opinion, but my opinion is that I feel like they shouldn't have done it, because we have been mostly safe when Trump was president. The reason we weren't completely safe is because people are hard headed and don't know how to follow instructions, so again I don't feel ike they should have done him like that, but everyone has their own opinion.
Step-by-step explanation:
Hope this helps!
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41.1 is the answer to this question.
Answer:
A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183
Step-by-step explanation:
Arranging the data set in order from least to greastest we get:
54, 68, 71, 72, 75, 84, 104, 108, 183
From this, we can see that the minimum value is 54 and the maximum value is 183.
Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median
To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).
Q1: 54, 68, 71, 72
68 + 71 = 139
139 ÷ 2 = 69.5
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Q3: 84, 104, 108, 183
104 + 108 = 212
212 ÷ 2 = 106
Option A is the only answer with all of these values, therefore, it is the answer.
hope this helps!
