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Lynna [10]
3 years ago
13

Given that (3, 2, –6) and (–2, 5, 1) are solutions of two equations in a system of three linear equations, which of the followin

g is true about the system?
A.) The system can only be consistent and independent.
B.) The system can be either inconsistent and independent or consistent and dependent.
C.) The system can be either inconsistent and dependent or consistent and independent.
D.) The system can only be inconsistent and dependent.
Mathematics
2 answers:
ELEN [110]3 years ago
5 0
I think the answer is b I hop I helped
Sergeeva-Olga [200]3 years ago
4 0

Answer:

The system can be inconsistent or consistent and  independent or consistent and  dependent.

Step-by-step explanation:

Consistent system: When the system of equation have atleast one solution then the system is consistent.

Inconsistent system: When the system of equation have no solution then the system is called inconsistent.

Dependent system: When the consistent system have infinite number of solutions then the system is called dependent.

Independent system: When the consistent system has exact one solution then the system is called independent system.

We are given two solutions of two equations are (3,2,-6) and (-2,5,1).

But the system of equations have three equations.

Then, the system of equations may have no solution or may have altleast one solution.

If given system of equations have no solutions then the system is inconsistent.

If the given system of equations have two or more than two solutions then the system is consistent and dependent.

If the given system of equations has exactly one solution then the system is consistent and independent.

The system can be inconsistent or consistent independent or consistent independent.

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The pilot of a Coast Guard patrol aircraft on a search mission had just spotted a disabled fishing trawler and decided to go in
Svetllana [295]

Answer:

\frac{dD}{dt}= 181\frac{168}{1600}

Step-by-step explanation:

h= 1000 ft

dx/dt= 232 ft/sec

D= 1600 ft

First, we have to find a distance x ( shown in the figure)

applying pythagorus theorem

D^2= h^2+x^2................1

x^2= D^2-h^2

= 1600^2-1000^2

x^2= 1560000

x=1248.99 m

Now we can find out how fast the aircraft is receding from the trawler

( notice that the height is not changing)

so differentiating equation 1 w.r.t t we get

\frac{d}{dt} (D^2)= \frac{d}{dt}(h^2+x^2)

2DD'= 2hh'+2xx'

D\frac{dD}{dt}= h\frac{dh}{dt}+x\frac{dx}{dt}

now putting values we get

1600\frac{dD}{dt}= 1000\times0+232\times1249

\frac{dD}{dt}= 181\frac{168}{1600}

6 0
3 years ago
PEASE HELP ASAP!!!!!!!
kiruha [24]
If u solve using the step by step equation process u will get the answer
4 0
3 years ago
Read 2 more answers
4(6c+5) - 2(3c - 5) = 120
ira [324]

Answer:

c=5

Step-by-step explanation:

Simplify both sides of the equation.

4(6c+5)−2(3c−5)=120

(4)(6c)+(4)(5)+(−2)(3c)+(−2)(−5)=120(Distribute)

24c+20+−6c+10=120

(24c+−6c)+(20+10)=120(Combine Like Terms)

18c+30=120

Subtract 30 from both sides.

18c+30−30=120−30

18c=90

Divide both sides by 18.

\frac{18c}{18}=\frac{90}{18}

c=5

hope this helps... :/

8 0
3 years ago
Read 2 more answers
Solve d=rt for t when r=75mph and d=450mi
madam [21]

Answer:

t = 6 hours

Step-by-step explanation:

First, we need to plug in our known information into d = rt.

450mi = \frac{75mi}{1hr} * t

450mi = 75mi * t --- simplify fraction

t = \frac{450}{75}

t = 6 hours

8 0
3 years ago
Keith has 500 in a savings account at the beginning of the summer he wants to have at least 200 at the end of the summer he with
Feliz [49]

Let w be the number of weeks. He withdraws $25 per week, so in w weeks, he withdraws 25w. He starts with $500, so after w weeks he has 500 - 25w. He wants this amount to be at least $200. "At least" means "greater than or equal to."

500 - 25w >= 200

-25w >= -300

w <= 12

Answer: Keith can withdraw $25 per week for at most 12 weeks.

8 0
3 years ago
Read 2 more answers
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