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viktelen [127]
3 years ago
5

Determine which consecutive integers do not have a real zero of f(x) = x3 + 5x2 - x - 6 between them.

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
4 0
The answer is c. I took the test
Karolina [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

I took the test, the answer is A, not c

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It is c since that is the answer
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I Have 10 Minutes Hurry for Brainlist and pls be accurate
yulyashka [42]

To find the equation we will put the values of x and y in the equations and then check if LHS=RHS.

\large\red{\sf{y=3x-1}}

  • x=1
  • y=9

\begin{gathered}\\ \sf\longmapsto 9=3(1)-1\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=3-1\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠2 \end{gathered}

\large\green{\sf{y=5x+4}}

\begin{gathered}\\ \sf\longmapsto 9=5(1)+4\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=5+4\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=9\end{gathered}

\large\blue{\sf{y=-2x-8}}

\begin{gathered}\\ \sf\longmapsto 9=-2(1)-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=-2-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠10\end{gathered}

\large\pink{\sf{y=6x-8}}

\begin{gathered}\\ \sf\longmapsto 9=6(1)-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=6-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠-2\end{gathered}

Hence, Option B. y=5x+4 satisfies the system (1,9)

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Step-by-step explanation:

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