1st day he ran30. 2nd day he ran 35 3rd day he ran 35 and fourth day he ran 45 so 30+35+35+45 =145 minutes all together he ran
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Isn't it (-3,3) that's what I think because it's 1 2 3 but I don't know
Answer:
Infinite solutions.
Step-by-step explanation:
Just plug your equation into desmos graphing calculator and it will graph it for you. If it is infinite the two lines will lay on top of one another. If there is only one solution it will be where the two lines intersect. If there are no solutions the two lines will be parallel.