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weqwewe [10]
3 years ago
9

Find four consecutive odd integers such that 5 times the sum of the first and the third is 15 more than 5 times the fourth.​

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

The required numbers are :

\boxed{ \boxed{ 5,7,9 \: and \: 11}}

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A piecewise function f(x) is defined as shown. f(x) = StartLayout enlarged left-brace 1st Row 1st column negative five-fourths x
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Answer:

(D)The first column is labeled x with entries 40, 160, 200. The second column is labeled y with entries 60, 15, 0.

Step-by-step explanation:

The piece-wise function, f(x) is defined as follows:

f(x)=\left\{\begin{array}{ccc}-\frac{5}{4}x+90 &0\leq x

f(0)=-\frac{5}{4}*0+90=90\\\\f(16)=-\frac{5}{4}*16+90=70\\\\f(40)=-\frac{3}{8}*40+75=60\\\\f(120)=-\frac{3}{8}*120+75=30\\\\f(160)=-\frac{3}{8}*160+75=15\\\\f(200)=-\frac{3}{8}*200+75=0

Therefore, the table which could represent the function is that which satisfies the points above.

In option D

\left|\begin{array}{c|c}x&f(x)\\--&--\\40&60\\160&15\\200&0\end{array}\right|

<u>The correct option is D</u>

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3 years ago
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djverab [1.8K]

Answer:

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