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lapo4ka [179]
3 years ago
13

Of five letters (a, b, c, d, and e), two letters are to be selected at random without replacement. how many possible selections

are there

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0
Sent a picture of the solution to the problem (s). I sent the formula because I do not know if your calculator has the combination function. You will notice the denominator. I got it by the 2 picks you make and the 3 from what is left over. The 5 is from the total selection.

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A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
A bakery sold a total of 500 cupcakes in a day, and 83% of them were vanilla flavored. How many of the cupcakes sold that day we
Hoochie [10]

Answer:

415 were vanilla

Step-by-step explanation:

To solve we must first turn the percentage into a number and multiply that by the sum of 500.

83% = .83

.83 x 500 = 415

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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MAVERICK [17]
No it is not because its more then ten numbers away from the solution of the five tickets
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gladu [14]

Answer:

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3 squared is 9. 5 squared is 25. 25 + 9 = 34. 5 + 3 = 8. So the smaller number is 3.

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