Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:
Answer: Question 1 :B,D.
Question 2:option B,
Question 3:Degree=5.
Question 4:option D.
Question 5: option c.
Step-by-step explanation:
1) A polynomial can not have any exponent as a variable or a fraction.
Options B and D are polynomials.
2) The polynomial is having 3 terms and is of degree 3.so it is a cubic trinomial Option B.
3) Degree is the highest power of the variables in the terms .The term 
has the power=3+2=5
So degree =5.
4)
Option D
5)
Simplifying like terms,
=
Option c.
Answer:
An estimate
Step-by-step explanation:
Answer:
i do not understand
Step-by-step explanation:
Answer:
-8±10x
Step-by-step explanation:
you will follow BODMAS
B=bracket
O= off
D=division
M=multiplication
A=addition
S=subtraction
2×3=6
7×2=14
[6-14±10x-8]÷[x-2]
14±8=22
6-22=-16
[-16±10x]÷[x-2]=-8±10x
