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Amanda [17]
3 years ago
5

What is the solution to the equation below 4w=2/3

Mathematics
2 answers:
julsineya [31]3 years ago
7 0
W= 1/6 hoped this helped:)
S_A_V [24]3 years ago
3 0

Answer:

w=1/6

Step-by-step explanation:

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Simplify -2 1/6 - ( -7 1/3 )
givi [52]

Answer:

5 1/6

Step-by-step explanation:

Note that - ( -7 1/3) = 7 1/3.  The two ' - ' signs cancel each other.

Thus, the original expression becomes -2 1/6  +  7 1/3.

Here the LCD is 6.  We re-write the above expression as -2 1/6 + 7 2/6.

Reversing the order of these terms makes the work a bit easier.

7 2/6 - 2 1/6 comes out to 5 1/6

6 0
3 years ago
Simplify the following square roots:
Gekata [30.6K]

Answer:

Sqrt32 = 4\sqrt{2}, Sqrt28 = 2\sqrt{7}, Sqrt12 = 2\sqrt{3}

Step-by-step explanation:

Square root of 32:

First we find the prime factors of the number by making a factor tree.

32 splits into 8 and 4.

8 splits into 4 and 2

4 splits into 2 and 2

4 splits into 2 and 2

This becomes the square root of 2^{2} x 2^{2} x 2. It will simplify to:

4\sqrt{2}

Square root of 28:

The prime factors of this number are:

2, and 2

This simplifies to 2\sqrt{7}

Square root of 12:

The prime factors of this are:

3, 2, 2

This simplifies to:

2\sqrt{3}

5 0
3 years ago
Read 2 more answers
Can somebody help me with Find 15% of $25
Zolol [24]

Answer:

$3.75

Step-by-step explanation:

This is the answer! Just trust me!

7 0
3 years ago
Read 2 more answers
How do you do negative and positive expressions?
Nataly [62]
Multiply the exponent outside the () with every exponent inside the ()
8 0
3 years ago
Joe has 37 coins consisting of nickels, dimes, and quarters. There are four more nickels than dimes and two more quarters than n
astraxan [27]

Answer:

  15

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters. The problem statement tells us ...

  n +d +q = 37

  n = d +4

  q = n +2

___

Rearranging the second equation gives ...

  d = n -4

Substituting that into the first, we get ...

  n + (n -4) +q = 37

  2n +q = 41 . . . . . . . add 4 and simplify

Rearranging the third original equation gives ...

  n = q -2

Substituting into the equation we just made, we get ...

  2(q -2) +q = 41

  3q = 45 . . . . . . . . add 4 and simplify

  q = 15 . . . . . . . . . divide by 3

Joe has 15 quarters.

_____

<em>Check</em>

The number of nickels is 2 fewer, so is 13. The number of dimes is 4 fewer than that, so is 9. The total number of coins is 15 + 13 + 9 = 37, as required.

5 0
3 years ago
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