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Dovator [93]
2 years ago
9

I need help please no links

Mathematics
2 answers:
Ilia_Sergeevich [38]2 years ago
7 0
Multiply by x and the answer should b A im pretty sure
Zigmanuir [339]2 years ago
3 0

Answer:

A and D

Step-by-step explanation:

Look at the answer choices as (x,y) so if you multiply the x for the x spot and the y for the y spot, you make sure the it is greater than or equal to 3 and if it is, select that answer.

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Polygons ! ( picture included)
mariarad [96]

Answer:

B

Step-by-step explanation:

2x+x=180

3x=180

x=60

2x=120

so B

hope that helps if it does please mark mine as brainliest.

8 0
3 years ago
Read 2 more answers
Jane cycled 32km, correct to the nearest km.
o-na [289]

Answer:

31.5

and

32,4

Step-by-step explanation:

4 0
2 years ago
The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO
Margarita [4]

Answer:

\angle PRQ = 80

Step-by-step explanation:

Given

\angle SPR = 145^o

\angle POT = 115^o

See attachment

Required

Find \angle PRO

First, calculate \angle RPO

\angle RPO + \angle SPR = 180 --- angle on a straight line

So, we have:

\angle RPO + 145 = 180

Collect like terms

\angle RPO = 180 - 145

\angle RPO = 35

Next, calculate PQR

\angle POR + \angle POT = 180

So, we have:

\angle POR + 115 = 180

Collect like terms

\angle POR = 180-115

\angle POR = 65

So, PRO is calculated as:

\angle PRO + \angle POR + \angle RPO = 180 --- angles in a triangle

So, we have:

\angle PRO + 65 + 35= 180

\angle PRO + 100= 180

Collect like terms

\angle PRO = 180-100

\angle PRO = 80

3 0
2 years ago
© Given that R= 9x + 8y
Phantasy [73]

Answer:

-19/9

Step-by-step explanation:

First, you would plug in the numbers for y and r. Therefore, your equation should now be 5 = 9x + 24. Now you would put like terms on the same side. It now then look like -19 = 9x. You divide by 9 to get the x by itself. The answer should be x = -19/9.

5 0
3 years ago
A basin is filled by two pipes in 12 minutes and 16 minutes respectively. Due to the obstruction of water flow after the two pip
olasank [31]

Answer:

The time duration of the two pipes restricted flow before the flow became normal is 4.5 minutes

Step-by-step explanation:

The given information are;

The time duration for the volume, V, of the basin to be filled by one of the pipe, A, = 12 minutes

The time duration for the volume, V, of the basin to be filled by the other pipe, B, = 16 minutes

Therefore, the flow rate of pipe A = V/12

The flow rate of pipe B = V/16

Due to the restriction, we have;

The proportion of its carrying capacity the first pipe, A, carries = 7/8 of the carrying capacity

The proportion of its carrying capacity the second pipe, B, carries = 5/6 of the carrying capacity

Whereby the tank is filled 3 minutes after the restriction is removed, we have;

\dfrac{7}{8} \times \dfrac{V}{12} \times t + \dfrac{5}{6} \times \dfrac{V}{16} \times t +  \dfrac{V}{12} \times 3 + \dfrac{V}{16} \times 3 = V

Simplifying gives;

\dfrac{(2\cdot t +7) \cdot V}{16}  = V

2·t + 7 = 16

t = (16 - 7)/2 = 4.5 minutes

Therefore, it took 4.5 seconds of the restricted flow before the the flow of water in the two pipes became normal

7 0
3 years ago
Read 2 more answers
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