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3 years ago

I need help please no links

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

Multiply by x and the answer should b A im pretty sure

Zigmanuir [339]3 years ago

3 0

Answer:

A and D

Step-by-step explanation:

Look at the answer choices as (x,y) so if you multiply the x for the x spot and the y for the y spot, you make sure the it is greater than or equal to 3 and if it is, select that answer.

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Expand the given power using the Binomial Theorem. (10k – m)5

agasfer [191]

Answer:

$(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

$(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}$

∵ The binomial is $(10k-m)^{5}$

∴ a = 10k , b = -m and n = 5

∴ $(10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}$

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ $(10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})$

∴ $(10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}$

5 0

3 years ago

What is the quotient of StartFraction 2 Superscript 4 Baseline Over 2 Superscript negative 4 Baseline EndFraction?

sp2606 [1]

Answer:

256

Step-by-step explanation:

I just did it right now

8 0

3 years ago

$8.50 with 6.5% markup

liraira [26]

Answer:

total would be $9.05

Step-by-step explanation:

$0.55 + $8.50

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3 years ago

Marta uses 1 peice of paper and 1 ribbon to make a kites.the papre comes in 3 packs and the ribbon comes in 4 packs.what is the

lianna [129]

If I'm understanding this correctly then 3 is your answer, but to be sure you'd have to be specific on how many papers and ribbons are in each pack.

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3 years ago

7x-21 . x2–5x+6<br> 5x +6<br> x+12

gogolik [260]

Answer:43

Step-by-step explanation:just Calculate all the numbers

7 0

3 years ago