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blagie [28]
3 years ago
15

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

, if necessary. units

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

Answer:

the answer is 38.25

Step-by-step explanation:

andre [41]3 years ago
7 0

Answer:

The perimeter is 38.25 units

Step-by-step explanation:

The perimeter of the tra-pezoid is the distance around it.

The length of the bases can be found using the absolute value method.

|RS|=|20-14|=6 units.

|TQ|=|22-8|=14

Recall the distance formula;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We use the distance to find the non parallel sides.

|ST|=\sqrt{(20-22)^2+(16-8)^2} =8.25 units.

and

|QR|=\sqrt{(8-14)^2+(16-8)^2} =10 units.

The perimeter of the tra-pezoid is

=14+10+6+8.25=38.25

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Answer:

x = 2.8

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Step-by-step explanation:

Reference angle = 45°

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Hypotenuse = x

Adjacent = y

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Sin 45 = Opp/Hyp

Sin 45 = 2/x

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Place each of the digits 1, 3, 5, and 6 in the blanks provided to create an expression whose value is 1/10
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Answer:

\frac{1}{5}\times \frac{3}{6}=\frac{3}{30}

Step-by-step explanation:

From the picture attached,

Multiplication of two fractions gives the result as \frac{1}{10}.

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3 years ago
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