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puteri [66]
3 years ago
10

Plz help due tonight

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

4x + 8 = 2x + 3 + 51 \\ 4x - 2x = 54 - 8 = 46 \\ 2x = 46 \\ x = 46 \div 2 = 23 \\ 2x + 3 = 2 \times 23 + 3 = 49 \\ 51 \\ 80

enjoy it

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Please write an equation
Katen [24]

Answer:

y = \frac{3}{4} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 5) ← 2 points on the line

m = \frac{5-2}{4-0} = \frac{3}{4}

The line crosses the y- axis at (0, 2 ) ⇒ c = 2

y = \frac{3}{4} x + 2 ← equation of line

4 0
2 years ago
Select the correct answer. In the figure, a pair of parallel lines is cut by a transversal. What kind of angle are angles A and
ankoles [38]

The answer is A. corresponding angles

7 0
3 years ago
Read 2 more answers
6 divided by 2 (1+2)
user100 [1]
Observe. 

6/2(1+2)
6/2(3)
6/6
1

Thus, the answer is: 1

4 0
3 years ago
Read 2 more answers
What is the answer to 1/2-1/5
Scorpion4ik [409]
First you need to find the common denominator. Think of a number that both 2 and 5 can go in to evenly. 10 is the best number, so, make both denominators 10. What you do to the bottom, you must do to the top.
Now your equation is 5/10-2/10
Your answer is 3/10
3 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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