Answer:
![- \frac{3}{4} \times \frac{p^{8} }{q^{3} }](https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7D%20%5Ctimes%20%20%5Cfrac%7Bp%5E%7B8%7D%20%7D%7Bq%5E%7B3%7D%20%7D)
Step-by-step explanation:
We have to find the quotient of the following division,
.
Now,
=
{Since all the terms in the expression are in product form, so we can treat them separately}
{Since we know the property of exponent as
}
=
=
(Answer)
{Since we know,
}
Convert 3 1/3 into a improper fraction:
= 10/3
Then flip the other fraction around and multiply them together:
1/3 -> 3/1
(10*3)/(3*1) = 30/3 = (30/3)/(3/3) = 10/1 = 10
The answer is 10
Answer:
![y=\frac{1}{3}x -4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%20-4)
Step-by-step explanation:
To write a linear function, use y=mx+b where m is the slope and b is the y-intercept. The y-intercept is where the line on the graph crosses the y-axis. On the graph is crosses at (0,-4). So b=-4. To find the slope, subtract the difference between two points on the line which cross through a grid line intersection. (0,-4) is one point. (3,-3) is another.
![\frac{-3--4}{3-0}=\frac{-3+4}{3} =\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B-3--4%7D%7B3-0%7D%3D%5Cfrac%7B-3%2B4%7D%7B3%7D%20%3D%5Cfrac%7B1%7D%7B3%7D)
Input 1/3 and b=-4 into y=mx+b.
![y=\frac{1}{3}x -4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%20-4)
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
Answer:
Th Range is [0, -∞)
Step-by-step explanation:
f(x) = 2 - x
w(x) = x - 2
We want to find the range of (f * w)(x).
First, we need to find (f * w)(x), which is the multiplication of the function f(x) and the function w(x). Lets use algebra to find (f * w)(x):
![(f*w)(x)=(2-x)(x-2)\\=2x-4-x^2+2x\\=-x^2+4x-4](https://tex.z-dn.net/?f=%28f%2Aw%29%28x%29%3D%282-x%29%28x-2%29%5C%5C%3D2x-4-x%5E2%2B2x%5C%5C%3D-x%5E2%2B4x-4)
This is a quadratic function (U shaped), or a parabola. The graph is attached.
The range is the set of y-values for which the function is defined.
We see from the graph that the parabola is upside down and the highest value is y = 0 and lowest goes towards negative infinity. So the range is from 0 to negative infinity. Or,
0 < y < ∞
In interval notation, that would be:
[0, -∞)