Answer:
The number of minutes advertisement should use is found.
x ≅ 12 mins
Step-by-step explanation:
(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)
<h3 /><h3>Step 1</h3>
For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.
Probability Density Function is given by:

Consider the second function:

Where Average waiting time = μ = 2.5
The function f(t) becomes

<h3>Step 2</h3>
The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01
The probability that a costumer has to wait for more than x minutes is:

which is equal to 0.01
<h3>
Step 3</h3>
Solve the equation for x

Take natural log on both sides

<h3>Results</h3>
The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger
Answer:
I think 83 ÷ 10 and it said that it incorrect
Step-by-step explanation:
Answer:
3x−4y=9 −3x+2y=9
Add these equations to eliminate x: −2y=18
Then solve−2y=18
for y: −2y=18 −2y −2 = 18 −2 (Divide both sides by -2)
y=−9
Now that we've found y let's plug it back in to solve for x.
Write down an original equation: 3x−4y=9
Substitute−9for y in 3x−4y=9: 3x−(4)(−9)=9
3x+36=9(Simplify both sides of the equation)
3x+36+−36=9+−36(Add -36 to both sides)
3x=−27 3x 3 = −27 3 (Divide both sides by 3) x=−9
Answer: x=−9 and y=−9
Hope This Helps!!!
Answer:
60 feet
Step-by-step explanation:
The height, h (in meters), of the object launched from a platform is represented by the equation

where x is the time (in seconds) passed after the launch.
The time of launch is
(0 seconds passed after the launch)
Substitute
to find the height:

<span>A unit </span>cube<span> is simply a </span>cube<span> measuring one inch, one centimeter, one </span>foot<span>, or whatever unit of measurement you are using, on all sides. ... </span>If<span> you look carefully, you will see that the </span>volume<span> of the</span>rectangular prism<span> is a function of multiplying the </span>length<span> the </span>width<span> the </span>height<span>. ... First find the </span>area<span> of the</span>base<span>. does that help</span>