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olchik [2.2K]
3 years ago
8

A house worth $250,000 has a coinsurance clause of 90 percent. The owners insure the property for $191,250. They then have a fir

e that causes $80,000 in damage. They will receive $______.00 from insurance.
Mathematics
2 answers:
scZoUnD [109]3 years ago
5 0

Answer:

$68,000 will be received from insurance

Step-by-step explanation:

250,000*.9=225000

$191,250/225,000=.85

.85*80,000=$68,000

This is the correct answer

yan [13]3 years ago
4 0

Answer: He will receive only $55080 against the fire insurance that caused damage the property.

Explanation:

Since we have given that a house worth $250,000 has a coinsurance clause of 90 percent .

But the owner insure the property for $191,250.

That means the owner does not insure the property for his full value ,

Amount incurred on fire that caused damage =$80,000

Amount he will receive against his insurance is given by

80000\times \frac{90}{100}\times \frac{191250}{250000}\\\\=\$55080

Hence, He will receive only $55080 against the fire insurance that caused damage the property.

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forsale [732]

Answer:

2/10 or 0.2

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John and O’Neill are playing a boardgame in which they roll to number cubes. John needs to get some of a on the number cubes to
Pani-rosa [81]

Answer: John is most likely to win.

Step-by-step explanation: John is most likely to win because he can roll the following numbers:

2,6

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Oh Neil Can only roll these numbers

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So John would most Likely win

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3 years ago
What is 4(x2 – 3x) + 12x2 + x simplified?<br> F 4x2–3x H 16x2–11x G13x2–2x I16x2–12x
Darina [25.2K]

Answer:

H 16x2–11x

Step-by-step explanation:

4(x2 – 3x) + 12x2 + x

4x^2-12x + 12x^2+x=

16x^2-11x

H 16x2–11x

3 0
3 years ago
There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved
Studentka2010 [4]
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
5 0
3 years ago
I need help with #2 and #6 pleaseeeeee
Mumz [18]

Answer:

Area of the rectangle = x² - 3x - 10

2019

Step-by-step explanation:

Length of the rectangle = x + 2

Width of the rectangle = x - 5

Area of the rectangle = length × width

= (x + 2) (x - 5)

= x² + 2x - 5x - 10

= x² - 3x - 10

Area of the rectangle = x² - 3x - 10

C = 20t² + 135t + 3050

Where

C = the number of new cars

t = year the number of new cars was purchased

t = 0 corresponds to 1998

Find the when c = 15,000

C = 20t² + 135t + 3050

15,000 = 20t² + 135t + 3050

20t² + 135t + 3050 - 15,000 = 0

20t² + 135t - 11,950 = 0

4t² + 27t - 2390 = 0

Solve using quadratic equation

t = -b ± √b² - 4ac / 2a

= -27 ± √27² - 4(4)(-2390) / 2(4)

= -27 ± √729 -(-38240) / 8

= -27 ± √729 + 38240 / 8

= -27 ± √38969 / 8

= -27/8 + √38969/8 or 27/8 - √38969/8

= -3.375 + 197.41/8 or -3.375 - 197.41/8

= -3.375 + 24.67625 or -3.375 - 24.67625

t = 21.30125 or - 28.05125

t cannot be negative

Therefore,

t = 21.30125

To the nearest whole number

t = 21

Recall,

t = 0 corresponds to 1998

Therefore

1998 + 21 = 2019

c = 15,000 in the year 2019

4 0
3 years ago
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