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3 years ago

HELP I'M REALLY BAD AT MATH! :D

Mathematics

2 answers:

Dmitrij [34]3 years ago

4 0

Answer:

i think 9

Step-by-step explanation:

it is there the most

sergiy2304 [10]3 years ago

3 0

Answer:

I think it's 9.

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Se desea constrir una barda utilizando block . las dimensiones de la barda son 25 m de largo y 2 m de altura . si se requieren 1

Andrew [12]

Answer:

I don't understand the language

Step-by-step explanation:

am not form Paris

3 0

3 years ago

A: b = 5:9 and b: c = 6:7. Find the simplest form of the ratio a:c.

OLga [1]

Answer:

5:7

Step-by-step explanation:

the answer remains the same

7 0

3 years ago

Read 2 more answers

Am I correct on question #6?

pashok25 [27]

Option A:

$\tan(105^\circ)=-(2+\sqrt{3})$

Solution:

To evaluate tan(105)°:

105° can be written as sum of 60° and 45°.

tan(105)° = tan(45 + 60)°

Using the summation identity:

$$\tan (x+y)=\frac{\tan (x)+\tan (y)}{1-\tan (x) \tan (y)}$

$$\tan \left(105^{\circ}\right)=\frac{\tan \left(45^{\circ}\right)+\tan \left(60^{\circ}\right)}{1-\tan \left(45^{\circ}\right) \tan \left(60^{\circ}\right)}$

We know that, tan(45)° = 1 and tan(60)° = √3

Substitute this in the above equation.

$$=\frac{1+\sqrt{3}}{1-1 \cdot \sqrt{3}}$

$$=\frac{1+\sqrt{3}}{1-\sqrt{3}}$

To rationalize the denominator multiply by the conjugate $\frac{1+\sqrt{3}}{1+\sqrt{3}}$ .

$$=\frac{(1+\sqrt{3})(1+\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})}$

Using exponent formula: $a^{b} \cdot a^{c}=a^{b+c}$ and $(x-y)(x+y)=x^2-y^2$

$$=\frac{(1+\sqrt{3})^2}{(1^2-(\sqrt{3})^2)}$

Using exponent formula: $(a+b)^{2}=a^{2}+2 a b+b^{2}$

$$=\frac{1^{2}+2 \cdot 1 \cdot \sqrt{3}+(\sqrt{3})^{2}}{1-3}$

$$=\frac{4+2 \sqrt{3}}{-2}$

$$=\frac{2(2+ \sqrt{3})}{-2}$

$=-(2+\sqrt{3})$

$\tan(105^\circ)=-(2+\sqrt{3})$

Hence option A is the correct answer.

6 0

4 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

katrin2010 [14]

Greetings and Happy Holidays!

1) Perpendicular to $-x+5y=14$
In order for lines to be perpendicular, their slopes must be negative reciprocals.
Example of slopes with negative reciprocals: 5 and $\frac{-1}{5}$

First, rearrange the equation into slope y-intercept form:
$-x+5y=14$

$5y=x+14$

$\frac{5y}{5}=\frac{x+14}{5}$

$y=\frac{1}{5}x+\frac{14}{5}$

The slope of the equation is: \frac{1}{5}

The negative reciprocal formula: $(m_{1})(m_{2})=-1$

Solve for the negative reciprocal:
$\frac{1}{5}m_{2}=-1$

Divide both sides by $\frac{1}{5}$
$\frac{\frac{1}{5}m_{2} }{ \frac{1}{5}} = \frac{-1}{ \frac{1}{5}}$

$m_{2}=(-1)(\frac{5}{1})$

$m_{2}=(\frac{-5}{1})$

$m_{2}=-5$

The slope of the new line is: -5

2) Passes through (-5,-2)

Create an equation with the slope discovered in slope y-intercept form.
$y=-5x+b$

Input the point the line passes through.
$(-2)=-5(-5)+b$

Solve for b (the y-intercept).
$-2=-5(-5)+b$

Multiply.
$-2=25+b$

Add -25 to both sides.
$(-2)+(-25)=b$

$-27=b$

The y-intercept is equal to -27

The Equation of the line is:
$y=-5x-27$

I hope this helped!
-Benjamin

6 0

4 years ago

Each dance class is hour. It takes a student 7 hours to learn a dance routine. Which

Sindrei [870]

Option 2 is your answer

7 0

3 years ago