Answer:
Step-by-step explanation:
three squares with known area 25, 144,169...
1) area of the square =25
Side ×side=25
Side^2=25
Side=√25
Side =5.
Answer is 5.
2) area of the square =144
Side ×side=144
Side^2=144
Side=√144
Side =12
Answer is 12.
3)area of the square =169
Side ×side=169
Side^2=169
Side=√169
Side =13
Answer is 13.
First we have to find the areas of both circle using the formula

For larger circle,

For smaller circle,

Required probability

Correct option is the second option .
Answer:X=5/6 Y=8/5
Step-by-step explanation:
-6x +5y=3
+6x
5y=6x+3 (divide each number by 5)
Y=6/5x + 3/5 (Plug that into your x equation)
12x+15 (6/5x + 3/5) =34
(Multiply 15 by the numbers in the brackets you can break it down and do 15•6 divided by 5 )
15•6=90 divided by 5=18x
15•3= 45 divided by 5=9
(Add like variables)
12x+18x=30x
30x+9=34
(Subtract 9 from itself do the same to 34)
9-9= 0
34-9=25
Divide 30 by itself to get x by itself then divide 25 by 30
25 divided by 30= 5/6
X=5/6 (plug that into the y equation)
Y=6/5•5/6+3/5
Multiply 6/5 and 5/6 straight across because this is multiplication you don't need like denominators
6/5•5/6=30/30=1
Y=1+3/5
1/1 + 3/5
Here you need to have like denominators because it is addition so just use 5
5•1=5
5/5+3/5=8/5
Y=8/5
the answer is 80 take the positive and negative and use the sign change rule
9514 1404 393
Answer:
9. ±1, ±2, ±3, ±6
11. ±1, ±2, ±3, ±4, ±6, ±12
Step-by-step explanation:
The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.
Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.
__
9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...
±{1, 2, 3, 6}
__
11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...
±{1, 2, 3, 4, 6, 12}
_____
A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)