Answer:
Step-by-step explanation:
You have the domain. It is given as -1≤x≤1
Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.
Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0
I've included a graph so you can see how this all works.
So the range = 1 ≤ y ≤ 3
The local gym holds three 45-minute workout sessions and two 30-minute sessions each week. Then the, total number of minutes Judy worked out for the week was 155 minutes.
We are to determine the total number of minutes Judy worked out for the week.
The gym holds three 45-minute workout sessions and two 30-minute sessions each week
So,
We can write,
The total number of minutes the gym holds workout sessions is
3 × 45 + 2 × 30
= 135 + 60
= 195 minutes
Also, from the information,
Judy left 5 minutes early during the 30-minute sessions and 10 minutes early during the 45-minute sessions.
The total number of minutes Judy didn't attend is
= 3 × 10 + 2 × 5
= 30 + 10
= 40 minutes
Then,
The total number of minutes Judy worked out for the week was,
= 195 minutes - 40 minutes
= 155 minutes
Therefore,
The total number of minutes Judy worked out for the week was 155 minutes.
To learn more about visit Calculating time :
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The answer is d because the x value does not repeat. Hopes this helps.
Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So

Probability of a defective item being produced on the first shift:
1% of 50%. So

What is the probability that it was manufactured during the first shift?

0.2941 = 29.41% probability that it was manufactured during the first shift.
Answer: 80
Write down all the values and cross out until you get to the middle, since there are 2 values, find the mean, which would be 80