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pantera1 [17]
3 years ago
7

if employee a logged 120 hours of travel in four years and employee b logged of travel at a 20% higher rate how many more hours

did employee be have that an employee after 1.5 years
Mathematics
1 answer:
Gnoma [55]3 years ago
6 0
First we need to find the rate of logging for employee A per year. To do this, the number of hours can be divided by the number of years to find out how many hours of travel they log per year.

120 ÷ 4 = 30. Employee A logs roughly 30 hours of travel per year.

To find a percentage increase of 20%, you need to multiply by 1.2. 
30 x 1.2 = 36. 
Therefore, Employee B logs roughly 36 hours of travel per year.

To find out how many hours of travel Employee B logs after 1.5 years, we simply need to multiply 36 by 1.5, which equals 54.

To find out how many hours of travel Employee A logs after 1.5 years, we simply need to multiply 30 by 1.5, which equals 45.

Finally, we need to find out how many MORE hours Employee B logged after 1.5 years compared to Employee A. To do this, we simply need to do 54 - 45 = 9 hours.

Working = (((120/4) x 1.2) x 1.5) - (120/4 x 1.5)
Answer = 9 hours.
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equation representing the given statement is ~

  • 50x + 330 \geqslant 820

The least number of lawns that he can cut and buy the computer is 10 lawns ~

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Total savings should be greater or equal to $ 820 in order to buy the computer,

And his total savinga is equal to ~

Money he saved + money got from cutting lawns.

let's assume the lawns cut by Tyrod be x,

Money earned by cutting lawns is equal to

  • total number of lawns cut × $50

  • 50x

total savings is equal to ~

  • 330 + 50x

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