Answer:
option B
hope its helpful
make me brainliest plz
sorry if it isn't correct
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
let, the days for 10 men be x
- 30/10=x/30
- 900=10x
- x=900/10
- x=90
so 10 men can complete the same work in 90days.
Hope it helps.
The measures of the angles are given to be x and y. Since y is 65 degrees less than the measure of angle x then, it can also be expressed as x - 65. The sum of the angles x and y should be 180 degrees as they are supplementary angles,
x + y = 180
x + (x - 65) = 180
The value of x is 122.5 and that of y is 57.5. Therefore, the measures of the angles are 122.5 and 57.5.
Answer:
1. Answer is C
4. Answer is G
Step-by-step explanation:
I'm not sure how to explain 1 since I used a calculator.
Number 4 is where you choose a point on the line and count 4 blocks up and 5 blocks left. If it hits another point on the line then that's the graph.