The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
X × x = x^2
x × -3 = -3x
3 × x = 3x
3 × -3 = -9
x^2 + 3x - 3x - 9
So I would agree with C because the -3x and the 3x cancel each other out. I hope this helps!
Answer:
56,000.0
Step-by-step explanation:
The number 6 is in the nearest thousand. To round, you look at the number in front of the number you are trying to round and decide if that number is higher or lower than five. If the number is higher than 5, round up to the next highest number. If the number is lower than 5, the number stays the same.
Area of Parallelogram = base x height
height = 4.5 cm
base = 4.5 cm x 2
height = 4.5 cm
base = 9 cm
9 cm x 4.5 cm = 40.50 cm^2
What’s something goes up but never comes down?
