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Inga [223]
2 years ago
13

Given IQ scores are approximately normally distributed with a mean of 100 and a standard deviation of 15 , the proportion of peo

ple with s above 130 is:
Mathematics
1 answer:
Snezhnost [94]2 years ago
5 0

Given the assumption of a normal distribution with a mean of 100 and a standard deviation of 15, a score of 130 represents a z-score of 2. In different mostly older handbooks of descriptive statistics you can find a ‘from z to percentile-table’. Nowadays it’s more easy to use the computer. Using R, a free and open source statistical environment (www.r-project.org), you can use the command pnorm (130, 100, 15) and it will give 0.9772. Because yo want the proportion above that score you use 1-pnorm (130, 100, 15). Another way of writing in R and with for example 3 IQ-scores:

perc = pnorm (c (70, 100, 130), 100, 15)

(1 - perc)

gives you the above-proportion of the IQ-scores of respectively 70, 100 and 130.

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11154 ÷ 52. Express the remainder as a fraction in the lowest terms
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11154/52= 214 1/2 is the answer to this question
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3 years ago
Which side in the smallest triangle would correspond with HI in the largest triangle?
tensa zangetsu [6.8K]

The side of the small triangle that will correspond to the side of HI is side IK.

<h3>How to find corresponding side of similar triangles?</h3>

Similar triangles are triangles that have the same shape but different size.

In similar triangles, corresponding sides are always in the same ratio.

The corresponding angles are equal.

Therefore, the side of the small triangle that will correspond to the side of HI is side IK.

learn more on triangle here: brainly.com/question/26531534

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5 0
2 years ago
Use order of operation and the mathematical properties of numbers to simplify these numbers (3+2^2)^2 =
Art [367]

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49

Step-by-step explanation:

(3+2²)²

(3+4)²

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49

3 0
3 years ago
Read 2 more answers
Write the given expression in terms of x and y only.<br> sin(sin−1(x) + cos−1(y))
yan [13]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2308127

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Write the expression below in terms of x and y only:

(I'm going to call it "E")

\mathsf{E=sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]\qquad\quad(i)}


Let

\begin{array}{lcl} \mathsf{\alpha=sin^{-1}(x)}&\qquad&\mathsf{then~-\,\dfrac{\pi}{2}\le \alpha\le \dfrac{\pi}{2}}\\\\\\ \mathsf{\beta=cos^{-1}(x)}&\qquad&\mathsf{then~0\le \beta\le \pi.} \end{array}


so the expression becomes

\mathsf{E=sin(\alpha+\beta)}\\\\ \mathsf{E=sin\,\alpha\,cos\,\beta+sin\,\beta\,cos\,\alpha\qquad\quad(ii)}


•   Finding \mathsf{sin\,\alpha:}

\mathsf{sin\,\alpha=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\alpha=x\qquad\quad\checkmark}


•   Finding \mathsf{cos\,\alpha:}

\mathsf{sin^2\,\alpha=x^2}\\\\ \mathsf{1-cos^2\,\alpha=x^2}\\\\ \mathsf{cos^2\,\alpha=1-x^2}\\\\ \mathsf{cos\,\alpha=\sqrt{1-x^2}\qquad\quad\checkmark}


because \mathsf{cos\,\alpha} is positive for \mathsf{\alpha\in \left[-\frac{\pi}{2},\,\frac{\pi}{2}\right].}


•   Finding \mathsf{cos\,\beta:}

\mathsf{cos\,\beta=cos\!\left[cos^{-1}(y)\right]}\\\\ \mathsf{cos\,\beta=y\qquad\quad\checkmark}


•   Finding \mathsf{sin\,\beta:}

\mathsf{cos^2\,\alpha=y^2}\\\\&#10; \mathsf{1-sin^2\,\beta=y^2}\\\\ \mathsf{sin^2\,\beta=1-y^2}\\\\ &#10;\mathsf{sin\,\beta=\sqrt{1-y^2}\qquad\quad\checkmark}


because \mathsf{sin\,\beta} is positive for \mathsf{\beta\in [0,\,\pi].}


Finally, you get

\mathsf{E=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}}\\\\\\ \therefore~~\mathsf{sin\!\left[sin^{-1}(x)+cos^{-1}(y)\right]=x\cdot y +\sqrt{1-y^2}\cdot \sqrt{1-x^2}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>inverse trigonometric trig function sine cosine sin cos arcsin arccos sum angles trigonometry</em>

6 0
3 years ago
You run 3 1/4 miles as a part of an exercise routine. You run 2/5 of that distance on a hill. You run down a slope for the last
irinina [24]

Answer:

Step-by-step explanation:

½ of ⅖ of 3¼ = ⅕ of 3¼

= ⅕ of 13/4

= 13/20

4 0
2 years ago
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