Angle 3 and angle 6 are corresponding angles, which means they are equal. In order for the lines to remain parallel, angle 3 and angle 6 would need to remain equal. If something is done to angle 6, then it would have to be done to angle 3 as well in order to keep the angles equal. So, if angle 6 is doubled, angle 3 would also have to be doubled.
The answer is B. m< 3 would need to double.
Hope this helps =)
Answer:
we have centre of circle as (30,40) and radius = 1
Step-by-step explanation:
Given that a car is moving on a circle on a plane.
At time t (seconds),
and
when we square and add both the equations we get
(since sin square + cos square = 1 always)
i.e. we have centre of circle as (30,40) and radius = 1
In order to sole the problem you need to create an equation to model what you are trying to do.
You end up with an equation looking like
25000*0.95^t
25000 is the starting value when t=0
95% is the amount remaining after the 5% decay
0.95 is being raised to the power of t to determine how many times it has decayed
When t=3 the equation should be
25000*0.95^3=21434.375
Answer:
-6
Step-by-step explanation:
We use PEMDAS to solve this,
so P stands for parentheses, so that's where we start.
We first, square the innermost parentheses with the exponent which is the E in PEMDAS, then then the outer parentheses
-12/3*(-8+16-6)+2
-12/3*(2)+2
Now we divide as in Division in PEMDAS.
-4*2+2
Now we multiply as in Multiplication in PEMDAS.
-8+2
Now we add as in A for Addition
-6
In PEMDAS, Multiplication doesn't always come before division, and same for addition and subtraction.
