Answer:
would be A
Step-by-step explanation:
because bisecting means both sides equal the same. so 4x-12 times two is 8x-24. Hope this helps
Answer:
9
Step-by-step explanation:
There would be 9 because 7 goes into 66 9 times
You have two triangles, ADC and ABC.
Sides AD and AB are congruent.
Sides DC and BC are congruent.
Side AC is congruent to itself.
By SSS, triangles ADC and ABC are congruent.
Corresponding parts of congruent triangles are congruent.
That means that angles DAC and BAC are congruent.
Angles DCA and BCA are congruent.
Since m<DAC = 32, then m<BAC = 32
Since m<DCA = 41, then m<BCA = 41.
Now you know the measures of two angles of triangle ABC.
The measures of the interior angles of a triangle add to 180.
You can find the measure of angle B.
m<BAC + m<B + m<BCA = 180
32 + m<B + 41 = 180
m<B + 73 = 180
m<B = 107
Answer:
Cone volume = [PI * radius ^ 2 * height] / 3 therefore,
Cone height = [3 * Cone Volume] / (PI * radius^2)
Step-by-step explanation:
Answer:
3√3
Step-by-step explanation:
For the problem shown here, your answer 3√3 is correct.
When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:
![\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B9%7D%7B%5Csqrt%7B3%7D%7D%3D%5Cdfrac%7B9%7D%7B%5Csqrt%7B3%7D%7D%5Ccdot%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%7D%3D%5Cdfrac%7B9%5Csqrt%7B3%7D%7D%7B3%7D%3D%5Cboxed%7B3%5Csqrt%7B3%7D%7D)
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If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.
<u>Example</u>:
![\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B9%7D%7B2-%5Csqrt%7B3%7D%7D%3D%5Cdfrac%7B9%7D%7B2-%5Csqrt%7B3%7D%7D%5Ccdot%5Cdfrac%7B2%2B%5Csqrt%7B3%7D%7D%7B2%2B%5Csqrt%7B3%7D%7D%3D%5Cdfrac%7B9%282%2B%5Csqrt%7B3%7D%29%7D%7B2%5E2-%28%5Csqrt%7B3%7D%29%5E2%7D%3D%5Cdfrac%7B18%2B9%5Csqrt%7B3%7D%7D%7B4-3%7D%5C%5C%5C%5C%3D%5Cboxed%7B18%2B9%5Csqrt%7B3%7D%7D)
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It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.
9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.
Please discuss this question with your teacher.