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Akimi4 [234]
3 years ago
10

I’m not sure what the last answer is. Please help!

Mathematics
2 answers:
alexira [117]3 years ago
5 0
D is true
Happy to help
earnstyle [38]3 years ago
4 0

Answer:

d) True

Step-by-step explanation:

m<BHC +m< CHD = m< BHD

Now, m<BHD = m< FHG = 90° ( vertically opposite angles)

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PLS HELP ASAP What pattern do you notice about the exponents when dividing two powers with the same base?
Tanya [424]

Answer:

subtract the exponents

Step-by-step explanation:

To divide powers of the same base, you can subtract the exponents.

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3 years ago
HELPP ASAP I’ll MARK YOu AS brainlister:(!!!
Lorico [155]

Answer:

69

Step-by-step

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3 years ago
Which number is the greatest? 0.35, 0.2, 0.56, 0.8, 0.09
ludmilkaskok [199]
I do believe it is 56
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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B2%7D%20%20-%204%20%20%5Cdiv%20%20%5Csqrt%7B3%7D%20%20-%202" id="TexFormula1" tit
ivann1987 [24]
Simplify the following:
(3 sqrt(2) - 4)/(sqrt(3) - 2)

Multiply numerator and denominator of (3 sqrt(2) - 4)/(sqrt(3) - 2) by -1:
-(3 sqrt(2) - 4)/(2 - sqrt(3))

-(3 sqrt(2) - 4) = 4 - 3 sqrt(2):
(4 - 3 sqrt(2))/(2 - sqrt(3))

Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/((2 - sqrt(3)) (sqrt(3) + 2))

(2 - sqrt(3)) (sqrt(3) + 2) = 2×2 + 2 sqrt(3) - sqrt(3)×2 - sqrt(3) sqrt(3) = 4 + 2 sqrt(3) - 2 sqrt(3) - 3 = 1:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1

((4 - 3 sqrt(2)) (sqrt(3) + 2))/1 = (4 - 3 sqrt(2)) (sqrt(3) + 2):
Answer: (4 - 3 sqrt(2)) (sqrt(3) + 2)
4 0
3 years ago
In circle P with mNRQ = 60°, find the angle measure of minor arc NQ
Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)

Multiply by 2 on both sides.

$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)

$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)

Substitute m∠NRQ = 60°.

$\Rightarrow 2\times 60^\circ=m(ar NQ)

$\Rightarrow 120^\circ=m(ar NQ)

The measure of minor arc NQ is 120°.

8 0
4 years ago
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