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OLEGan [10]
3 years ago
8

What is the solution of log2x+7 27= 3

Mathematics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

x=-2

Step-by-step explanation:

log_{2x+7}(27)= 3

We need to find the value of x

WE write the given log equation in exponential form'

log_b(a)=x can be written as b^x=a

Using this we convert log to exponential form

log_{2x+7}(27)= 3

(2x+7)^3= 27

27 can be written as 3^3

(2x+7)^3= 3^3

Both sides have exponent 3. To remove exponent 3 we take cube root on both sides.

2x+7=3

Subtract 7 on both sides

2x=-4

Divide both sides by 2

x=-2

KATRIN_1 [288]3 years ago
5 0
log_{2x+7} 27=3
(2x+7)^3=27
2x+7= \sqrt[3]{27}
2x+7=3
2x=-4
x=-2
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