Question

What is the solution of log2x+7 27= 3

Answer 1

Answer:

$x=-2$

Step-by-step explanation:

$log_{2x+7}(27)= 3$

We need to find the value of x

WE write the given log equation in exponential form'

$log_b(a)=x$ can be written as $b^x=a$

Using this we convert log to exponential form

$log_{2x+7}(27)= 3$

$(2x+7)^3= 27$

27 can be written as 3^3

$(2x+7)^3= 3^3$

Both sides have exponent 3. To remove exponent 3 we take cube root on both sides.

$2x+7=3$

Subtract 7 on both sides

$2x=-4$

Divide both sides by 2

$x=-2$

Answer 2

$log_{2x+7} 27=3$
(2x+7)^3=27
$2x+7= \sqrt[3]{27}$
2x+7=3
2x=-4
x=-2