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Brilliant_brown [7]
3 years ago
6

Three different rectangles have an area of 20. What are the possible whole-number dimensions of the rectangles?

Mathematics
1 answer:
Firlakuza [10]3 years ago
4 0
L = 20 W = 1
L = 10 W = 2
L = 5 W = 4

Study this carefully. It's a good problem to know how to do. The ancients solved problems by using this method. They started with biggest number they could on the left and multiply each number on the right as they went down (in this case by 2).
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If a town with a population of 1,000 doubles in size every 46 years, what will the population be 92 years from now?
Natalija [7]

Answer:

3,000 or 2,000 depends of where it starts at zero or 1,000

Step-by-step explanation:

3 0
3 years ago
Which of the following rational functions is graphed below?
AlekseyPX

Answer:

The rational function that is graphed is B

6 0
2 years ago
Read 2 more answers
Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?
Yuliya22 [10]
<span>–4(x + 3) ≤ –2 – 2x

>>.....-4x -12 </span>≤ -2 -2x

>>  -12 +2 ≤ +2x 

>> - 10 ≤ 2x

>> -5 ≤ x............>> x >= -5 

This answer is not represented in the pictures you attached

The line starts in x = -5 and goes up to infinity
3 0
3 years ago
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Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-pound box of crackers for $4.68. The unit price at P
Vesna [10]

Answer:

The unit price at Price-Club is $0.2158 per ounce.

The unit price at Shop Mart is $0.2925 per ounce.

Step-by-step explanation:

Price Club:

12-ounce box of crackers for $2.59

So

12 ounces - $2.59

1 ounce - x

12x = 2.59

x = \frac{2.59}{12}

x = 0.2158

The unit price at Price-Club is $0.2158 per ounce.

Shop Mart:

1-pound box of crackers for $4.68.

1 pound is 16 ounces. So

16 ounces - $4.68

1 ounce - x

16x = 4.68

x = \frac{4.68}{16}

x = 0.2925

The unit price at Shop Mart is $0.2925 per ounce.

8 0
3 years ago
Helppppppppppppppppppp please
Svetlanka [38]

Answer:

\sqrt[]{\frac{x+8}{4}}-3

Step-by-step explanation:

g(x)=4(x+3)^2-8

First rewrite g(x) as y

y=4(x+3)^2-8

Now swap y and x

x=4(y+3)^2-8

Add 8 on both sides.

x+8=4(y+3)^2-8+8

x+8=4(y+3)^2

Divide by 4.

\frac{x+8}{4} =\frac{4(y+3)^2}{4}

\frac{x+8}{4}=(y+3)^2

Extract the square root on both sides.

\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}

\sqrt[]{\frac{x+8}{4}}=y+3

Subtract 3 on both sides.

\sqrt[]{\frac{x+8}{4}}-3=y+3-3

\sqrt[]{\frac{x+8}{4}}-3=y

4 0
3 years ago
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