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meriva
3 years ago
6

Find the value of 24/25 divided by 4/5

Mathematics
1 answer:
Archy [21]3 years ago
3 0
The answer to the question is 0.048
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The senior classes at High School A and High School B planned separate trips to the county fair. The senior class at High School
elena-s [515]

vans = v, buses = b, students = s

8v + 8b =312s ...eqn 1

9v + 4b = 196s ...eqn 2

divide eqn 1 by 2

4v + 4b = 156s ...eqn 3

eqn 2 - eqn 3

5v = 40s

v = 8s

subst v = 8s in eqn 2

72s + 4b = 196 s

b = 31s

answer

each van holds 8 students and each bus holds 31 students

8 0
3 years ago
A bank account has an initial deposit of $14,000. After 8 years, the bank account
Kamila [148]

Answer:

2.3%

Step-by-step explanation:

18000 = 15000( 1 + i)^8

Divide both sides by 15000

1.2 = (1 + i)^8

Take both sides to the 1/8 power

1.2^(1/8) = 1 + i

1.023051875220463 = 1 + i

Subtract 1 from both sides

i = 0.023051875220463

~ 2.3%

8 0
3 years ago
Can someone help me with this and explain it?
Softa [21]

Answer:

4 pizzas

Step-by-step explanation:

Equation:

12x + 7 = 55

12x = 55 - 7

12x = 48

x = 4

4 0
3 years ago
Find the following:1) 30% of 90​
irinina [24]

Answer:

27

Step-by-step explanation:

30/100 ×90 is 27.

it's making me type more but that's the answer :)

3 0
3 years ago
Read 2 more answers
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
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