The two sides are equal and for that reason DE = CE as shown below :
AD = BC, DF = GC
E = A(F) and E = BG, therefore A(F) = BF
<h3>Description of rectangle</h3>
Now we all know that a rectangle has four edges which are A, B, C, D.
when we divide the bottom line, which is the line from point C to D into three parts we will have ( DF, FG, and GC )
From the question we know that DF = GC
E is the intersection of A(F) and BG
we can now Prove that DE = CE.
since D and C are point included in E and since this is a rectangle
AD = BC, DF = GC
E = A(F) and E = BG, therefore A(F) = BF
DE = CE
We can conclude by saying that in a rectangle two sides are equal and for that reason DE = CE
Learn more about Rectangle : brainly.com/question/22148953
Answer:
17) 26
18) 66
19) 78
20) 145
Step-by-step explanation:
#17) 8 + 3n for n = 6
8 + 3*(6)
8 + 18 = 26
#18) (8 + 3)n for n = 6
(8 + 3)*6
(11)*6 = 66
#19) 90 - 4d for d = 3
90 - 4*(3)
90 - 12 = 78
#20) 7x + 2y for x = 15, y = 20
7*(15) + 2*(20) = 145
Answer:
a+2b-d=1, 3, 5, 7
Step-by-step explanation:
(ax^2+bx+3)(x+d)
ax^3+bx^2+3x+adx^2+bdx+3d
ax^3+bx^2+adx^2+3x+bdx+3d=x^3+6x^2+11x+12
ax^3=x^3, a=1
bx^2+adx^2=6x^2
x^2(b+ad)=6x^2
b+ad=6
b+(1)d=6
b+d=6
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3x+bdx=11x
x(3+bd)=11x
3+bd=11
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b=6-d
3+(6-d)d=11
3+6d-d^2=11
3-11+6d-d^2=0
-8+6d-d^2=0
d^2-6d+8=0
factor out,
(d-4)(d-2)=0
zero property,
d-4=0, d-2=0
d=0+4=4,
d=0+2=2
b=6-4=2,
b=6-2=4.
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a+2b-d=1+2(2)-2=1+4-2=5-2=3
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a+2(4)-4=1+8-4=9-4=5
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a+2(2)-4=1+4-4=5-4=1
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a+2(4)-2=1+8-2=9-2=7
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