All categories

3 years ago

What do scientists use to predict the locations of electrons in atoms?

1 answer:

8 0

The probable answer would be A.Probability. This is because there are no certain ways to tell where the exact location of the electrons. Through probability, we can derive the closest location that the electrons are located and the energy they have.a

You might be interested in

An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and

Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic fields of strengths B = 0.1250 T

The diameter d is 25.05 cm which is converted to 0.2505m

The radius is (d/2)

= 0.2505m / 2 = 0.12525m

The given formula to find the magnetic force is $F_{ma}=BqV---(i)$

The given formula to find the electric force is $F_{el}=qE---(ii)$

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

$Bqv=qE\\\\v=\frac{E}{B}$

$v=\frac{187500}{0.125} \\\\v=15\times10^5m/s$

It is said that the particles moves in semi circle, so we are going to consider using centripetal force

$F_{ce}=\frac{mv^2}{r}---(iii)$

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

$Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br} \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg$

Therefore, the particle's charge-to-mass ratio is $958.1\times10^5C/kg$

To identify the particle

Then 1/ 958.1 × 10⁵ C/kg

The charge to mass ratio is very close to that of a proton, which is about 1*10^8 C/kg

Therefore the particle is proton.

8 0

4 years ago

agasfer [191]

The distance between the plates is 7.1 * 10^-7 m

<h3>What is the distance?</h3>

The capacitor is a device that is used to store charges. The capacitor always has a dielectric that is placed between the capacitors that separates them.

Given that;

C = εoA/d

C = capacitance

εo = permittivity of free space

A = cross sectional area

d = distance apart

Cd = εoA

d = εoA/C

d = 8.8 * 10^-12 * 8.89 * 10^-4/1.11 * 10^-8

d = 7.1 * 10^-7 m

Learn more about capacitor:brainly.com/question/17176550

#SPJ1