Ask question

Ask question

All categories

3 years ago

11

two cars go through 2 different crashes. car one 1 experiences a 500N impulse for a duration for 15s, while car2 experiences the

same impulse for a duration of 5s which car experiences the most force during their collison

1 answer:

likoan [24]3 years ago

7 0

Answer:

Conservation of momentum.

Momentum is zero after collision, no direction or speed.

Explanation:

You might be interested in

An object moving on a horizontal, frictionless surface makes a glancing collision with another object initially at rest on the s

ivann1987 [24]

Answer:

A) Momentum is always conserved, and kinetic energy may be conserved. TRUE

(B) Kinetic energy is always conserved, and momentum may be conserved. FALSE

(C) Momentum is always conserved, and kinetic energy is never conserved. FALSE

(D) Both momentum and kinetic energy are always conserved.

FALSE

(E) Neither momentum nor kinetic energy is conserved.

FALSE

Explanation:

A) Momentum is always conserved, and kinetic energy may be conserved.

Always the momentum is conserved for any collision.

(B) Kinetic energy is always conserved, and momentum may be conserved.

In inelastic collison the Kinetic energy is not conserved.

(C) Momentum is always conserved, and kinetic energy is never conserved.

For elastic collision the kinetic energy is always conserved.

(D) Both momentum and kinetic energy are always conserved.

The kinetic energy never is conserved in an inelastic collision.

(E) Neither momentum nor kinetic energy is conserved.

The momentum always is conserved.

7 0

4 years ago

What is the distance traveled when you stretch a rubber band 15 cm?

mrs_skeptik [129]

Answer:

15 cm

Explanation:

common sense

3 0

3 years ago

A charge of 1.0 × 10-6 μC is located inside a sphere, 1.25 cm from its center. What is the electric flux through the sphere due

Korvikt [17]

Answer:

$\Phi_E=0.11\frac{N\cdot m^2}{C}$

Explanation:

According to Gauss's Law, the electric flux of a charged sphere is the electric field multiplied by the area of the spherical surface:

$\Phi_E=EA\\\Phi_E=E(4\pi R^2)\\\Phi_E=\frac{q}{4\pi \epsilon_0 R^2}(4\pi R^2)\\\Phi_E=\frac{q}{\epsilon_0}$

This is identical to the electric flux of a point charge located in the center of the sphere.

$\Phi_E=\frac{1*10^{-12}C}{8.85*10^{-12} \frac{C^2}{N\cdot m^2}}\\\Phi_E=0.11\frac{N\cdot m^2}{C}$

8 0

4 years ago

(HELP PLEASEE) An object is 40.0 cm from a

PilotLPTM [1.2K]

Answer:

-18

Explanation:

acellus use the formula of magnification and watch your minus sign

6 0

3 years ago

A block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp

GuDViN [60]

The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

<h3>What is work done?</h3>

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.

From the Newton's law of motion,

ma =F-mg sinθ =0

So, the force F = mg sinθ

Plug the values, we get

F = 620N x sin 23.5°

F = 247.224 N

Work done by motor is W= F x d

The force is equal to the weight F = mg

So, W = 247.224 x 14.1

W = 3.486 kJ

Thus, the work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.

Learn more about Work done

brainly.com/question/13662169

#SPJ1

7 0

2 years ago