All categories

2 years ago

This is Yolanda's desk. What could Yolanda do to increase the amount of force needed to change the motion of the desk?

Physics

1 answer:

Stella [2.4K]2 years ago

8 0

Yolanda might put more items to the desk to make it heavier, requiring more force.

We need to learn more about the force acting on an object in order to locate the solution.

<h3>How can the force that is required to modify the motion be increased?</h3>

We are aware that the word for force is,

F=ma

where m denotes the object's mass and an its acceleration

There are two ways to increase the force required to alter the motion of the table.

One is to increase the mass, and the other is to accelerate it more quickly.

Otherwise, there will be a lot of friction between the surfaces, making it difficult to move without exerting a lot of force.

We can infer from this that Yolanda could add items to the desk to increase its mass, necessitating the use of additional force.

Learn more about the force here:

brainly.com/question/4075805

#SPJ1

You might be interested in

What types of crust are colliding between the North American Plate and the Pacific Plate?

svet-max [94.6K]

Answer: G00gle got you bro

Explanation:

Yea

4 0

3 years ago

The fast train known as the TGV (Train à Grande Vitesse) that runs south from Paris, France, has a scheduled average speed of 21

andrezito [222]

Answer:

Explanation:

Given

average speed of train $(v_{avg})=216 kmph\approx 60 m/s$

Maximum acceleration=0.05g

Now centripetal acceleration is

$a_c=\frac{v^2}{r}$

$0.05\times 9.8=\frac{60^2}{r}$

r=7346.93 m

(b)Radius of curvature=900 m

therefore $a_c=\frac{v^2}{r}$

$v=\sqrt{a_cr}$

$v=\sqrt{0.05\times 9.8\times 900}$

$v=\sqrt{441}=21 m/s$

8 0

4 years ago

A child throws a ball with an initial speed of 8.00 m/s at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00

vivado [14]

Answer:

7.5 m

Explanation:

$v$ = initial speed of the ball = 8 m/s

$\theta$ = angle of launch = 40° deg

Consider the motion along the vertical direction :

$v_{oy}$ = initial velocity along vertical direction = $v Sin\theta$ = 8 Sin40 = 5.14 m/s

$a_{y}$ = acceleration along vertical direction = - 9.8 m/s²

$t$ = time of travel

$y$ = vertical displacement = - 1 m

Using the kinematics equation

$y = v_{oy}t + (0.5)a_{y}t^{2}$

$- 1 = (5.14)t + (0.5)(- 9.8)t^{2$

$t$ = 1.22 sec

Consider the motion along the horizontal direction :

$v_{ox}$ = initial velocity along horizontal direction = $v Sin\theta$ = 8 Cos40 = 6.13 m/s

$a_{x}$ = acceleration along vertical direction = 0 m/s²

$t$ = time of travel = 1.22 sec

$x$ = horizontal displacement = ?

Using the kinematics equation

$x = v_{ox}t + (0.5)a_{x}t^{2}$

$x = (6.13)(1.22) + (0.5)(0)(1.22)^{2$

$x$ = 7.5 m

4 0

3 years ago

An attack helicopter is equipped with a 20- mm cannon that fires 87 g shells in the forward direction with a muzzle speed of 853

uysha [10]

Answer

given,

mass of the shell = 87 g = 0.087 Kg

speed of the muzzle = 853 m/s

mass of the helicopter = 4410 kg

A burst of 176 shell fired in 2.93 s

resulting average force = ?

momentum of the shell = m v

= 0.087 x 853

= 74.21 kgm/s

momentum of 176 shell is = 176 p

= 176 x 74.21

= 13060.96

momentum of helicopter = - 13060.96 kgm/s

amount of speed reduce a = $\dfrac{13060.96}{M}$

a= $\dfrac{13060.96}{4410}$

a = 2.96 m/s²

velocity = \dfrac{2.96}{2.93}

v = 1.01 m/s

5 0

3 years ago

Read 2 more answers

If the change in velocity increases, what happens to the acceleration during the same time period?

4vir4ik [10]

When the velocity is increasing the acceleration increases too

4 0

3 years ago

Read 2 more answers