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AnnyKZ [126]
1 year ago
12

This is Yolanda's desk. What could Yolanda do to increase the amount of force needed to change the motion of the desk?

Physics
1 answer:
Stella [2.4K]1 year ago
8 0

Yolanda might put more items to the desk to make it heavier, requiring more force.

We need to learn more about the force acting on an object in order to locate the solution.

<h3>How can the force that is required to modify the motion be increased?</h3>
  • We are aware that the word for force is,

                            F=ma

where m denotes the object's mass and an its acceleration

  • There are two ways to increase the force required to alter the motion of the table.
  • One is to increase the mass, and the other is to accelerate it more quickly.
  • Otherwise, there will be a lot of friction between the surfaces, making it difficult to move without exerting a lot of force.

We can infer from this that Yolanda could add items to the desk to increase its mass, necessitating the use of additional force.

Learn more about the force here:

brainly.com/question/4075805

#SPJ1

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Answer:

The speed of the big fish after swallowing the small fish is 0.38 m/s.

Explanation:

Consider west to east direction as positive and the opposite direction as negative.

Given:

Mass of big fish (m₁) = 12.0 kg

Initial velocity of big fish (u₁) = 75 cm/s = 0.75 m/s

Mass of small fish (m₂) = 1 kg

Initial velocity of small fish (u₂) = -4 m/s (Direction is opposite to u₁)

After swallowing the small fish, both the fishes move together with same velocity. Let the velocity be 'v'.

So, as there are no effects of drag or any other forces, the given scenario can be considered as a case of inelastic collision where the objects move together with same velocity after collision.

The momentum is conserved in inelastic collision. Therefore,

Initial momentum of the fishes = Final momentum of the fishes

m_1u_1+m_2u_2=(m_1+m_2)v\\\\v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}

Now, plug in the given values and solve for 'v'. This gives,

v=\frac{12.0\times 0.75+1\times (-4)}{12.0+1}\\\\v=\frac{9-4}{13}\\\\v=\frac{5}{13}=0.38\ m/s

Therefore, the speed of the big fish after swallowing the small fish is 0.38 m/s

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