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2 years ago

This is Yolanda's desk. What could Yolanda do to increase the amount of force needed to change the motion of the desk?

Physics

1 answer:

Stella [2.4K]2 years ago

8 0

Yolanda might put more items to the desk to make it heavier, requiring more force.

We need to learn more about the force acting on an object in order to locate the solution.

<h3>How can the force that is required to modify the motion be increased?</h3>

We are aware that the word for force is,

F=ma

where m denotes the object's mass and an its acceleration

There are two ways to increase the force required to alter the motion of the table.

One is to increase the mass, and the other is to accelerate it more quickly.

Otherwise, there will be a lot of friction between the surfaces, making it difficult to move without exerting a lot of force.

We can infer from this that Yolanda could add items to the desk to increase its mass, necessitating the use of additional force.

Learn more about the force here:

brainly.com/question/4075805

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Why is freshly distilled or deionized water used in this standardization?

sukhopar [10]

Answer:

The amount of carbon dioxide is little in deionized water.

Explanation:

Deionized water is a water with little or no impurities. Impurities are in waters are not able to boil below or above the boiling point of water,and in this case are been retained in the original container.

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3 years ago

Read 2 more answers

510 g squirrel with a surface area of 935 cm2 falls from a 4.8-m tree to the ground. Estimate its terminal velocity. (Use the dr

Yuki888 [10]

Answer:

The terminal velocity is $v_t =17.5 \ m/s$

Explanation:

From the question we are told that

The mass of the squirrel is $m_s = 50\ g = \frac{50}{1000} = 0.05 \ kg$

The surface area is $A_s = 935 cm^2 = \frac{935}{10000} = 0.0935 \ m^2$

The height of fall is h =4.8 m

The length of the prism is $l = 23.2 = 0.232 \ m$

The width of the prism is $w = 11.6 = 0.116 \ m$

The terminal velocity is mathematically represented as

$v_t = \sqrt{\frac{2 * m_s * g }{\dho_s * C * A } }$

Where $\rho$ is the density of a rectangular prism with a constant values of $\rho = 1.21 \ kg/m^3$

$C$ is the drag coefficient for a horizontal skydiver with a value = 1

A is the area of the prism the squirrel is assumed to be which is mathematically represented as

$A = 0.116 * 0.232$

$A = 0.026912 \ m^2$

substituting values

$v_t = \sqrt{\frac{2 * 0.510 * 9.8 }{1.21 * 1 * 0.026912 } }$

$v_t =17.5 \ m/s$

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3 years ago

Uranium has two naturally occurring isotopes. 238u has a natural abundance of 99.3% and 235u has an abundance of 0.7%. it is the

dmitriy555 [2]

The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.

The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.

The rms speed is calculated as

v=√(3RT/m)

Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as

r=√(352/349)=1.004

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3 years ago

How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?

ExtremeBDS [4]

Answer:

The value is $T = 122036.2 \ N$

Explanation:

From the question we are told that

The mass of the car is $m = 6526 \ kg$

The acceleration is $a= 8.9 \ m/s^2$

Generally the net force applied on the rope is mathematically represented as

$F_{net} = T - W$

Here W is the weight of the car which is evaluated as

$W = m * g$

=> $W = 6526 * 9.8$

=> $W = 63954.8 \ N$

Generally the net force can also be mathematically represented as

$F = m * a$

$m * a = T - 63954.8$

=> $6526 * 8.9 = T - 63954.8$

=> $T = 122036.2 \ N$

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3 years ago

A surfer is moving at a constant velocity of 5.2 m/s north relative to a wave which is pushing him west at a constant velocity o

Vika [28.1K]

The speed and distances are directly proportional. Use ratios to solve for vertical y-distance. The ratio of x-distance west to y-distance north equals the x-velocity to y-velocity.

x/y = vx/vy
41/y = 8.6/5.2
41/y = 1.65
41/1.65 = y
24.8 m = y

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3 years ago