All categories

3 years ago

Which of the following is a factor of 12 X squared minus 4X minus one

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

5 0

Answer:

You can factor it as (6x+1)(2x-1)

You can also give me brainliest please.

Agata [3.3K]3 years ago

4 0

<u>Answer:</u>

The factor of 12x squared minus 4x minus one is (6x + 1) and (2x – 1)

<u>Solution:</u>

Need to determine factors 12 x squared minus 4x minus one

This means that we need to factorize following expression

$12 x^{2}-4 x-1$

On splitting the middle term in such a way that sum of two split terms must be -4x and product of two split terms must be $-12 x^{2}$ we get,

$12 x^{2}-6 x+2 x-1$

$=> 6x(2x -1) + 1 (2x - 1 )$

Combining the terms we get

=> (6x + 1) (2x – 1)

Hence factors of $12 x^{2}-4 x-1$ is (6x + 1) and (2x – 1)

You might be interested in

Ania scored a total of 120 points this season so far and averaged 15 points a game. How many games has she played?

arlik [135]

She played 8 games. Since she earned a total of 120 points and 15 points per game you would divide 120/15=8

4 0

3 years ago

What is the quotient (3x^2+8x-3)/ (x+3)

Dvinal [7]

Answer:

The quotient ix 3x - 1.

Explanation:

Use Long division:

3x - 1 <------------quotient.

---------------------

x + 3) 3x^2 + 8x + 3

3x^2 + 9x

-------------

-x + 3

-x - 3

------

6 <---------remainder.

6 0

3 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

U-3/4=4 please help me ty

Ne4ueva [31]

To solve the equation:

$\frac{u - 3}{4} = 4 \\ \frac{u - 3}{4} \times 4 = 4 \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19$

Therefore, the answer is u=19.

Hope it helps!

8 0

4 years ago

Read 2 more answers

One hundred students were surveyed about their preference between dogs and cats. The following two-way table displays data for t

jenyasd209 [6]

Hi, did you forget to attach the two-way table to the question? I can't seem to see it, so I can't answer your question

8 0

3 years ago