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densk [106]
3 years ago
14

A cupboard contains 5 pairs of shoes, each of a different style. How many ways are there to select 4 of the shoes from the cupbo

ard so that the selection contains exactly one matching pair? Note that each pair of shoes consists of distinguishable left and right foot.
Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0
The solution to the problem is as follows:

If there are 6 pairs of shoes:

C(6,1) = choose the matching pair = 6 choices. 
C(10,1) = 1 shoe from the other 10. 
Now you cannot choose the mate of that one, 
so you have 8 other shoes to choose from. 

6 * 10 * 8 = 480 choices of "4 shoes". 
But then we must divide by 2, because the last two shoes 
could be chosen in either order. 

That gives 240 choices - same as your teacher's answer, 
<span>but via a different route. 
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r
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The value of q(x) is 2 x+5

The value of r(x) is 6

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The given expression is \frac{2 x^{2}+13 x+26}{x+4}

We need to rewrite the expression in the form of q(x)+\frac{r(x)}{b(x)}

Simplifying the expression, we get,

\frac{2 x^{2}+8 x+5x+26}{x+4}

Separating the fractions, we have,

\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}

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Now, we shall further simplify the term \frac{5 x+26}{x+4} , we get,

\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}

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q(x)=2 x+5

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