<h2>
Step-by-step explanation:</h2>
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
<u>Case 1 :-</u> When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
<u>Case 2 :-</u> when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1
This can be a right triangle
Answer:
0.08065
Step-by-step explanation:
Given that in a recent study,1 2006 randomly selected US adults (age 18 or older) were asked to give the number of people in the last six months with whom you discussed matters that are important to you.
If X is random variable then X has mean 2.2 and s = 1.4
n=2006
Std error of mean =
For 99% since sample size is large, t and z distn almost coincide.
Hence we can take 2.58 as critical value
Margin of error at 99% =
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
<span> x^2-14*x+31-(63)=0 </span><span>x = 16
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