All categories

3 years ago

Write the following equations in slope intercept form Equation 1: y-7x=6 Equation 2: y+7x=8

Mathematics

2 answers:

Tomtit [17]3 years ago

6 0

Answer:

Equation 1: y = 7x + 6

Equation 2: y = -7x + 8

Step-by-step explanation:

Isolate the y variables in both equations

Equation 1:

y - 7x = 6

y = 7x + 6

Equation 2:

y + 7x = 8

y = -7x + 8

So, the equations in slope intercept form are:

Equation 1: y = 7x + 6

Equation 2: y = -7x + 8

slamgirl [31]3 years ago

6 0

Answer:

Find the value of b using the formula for the equation of a line. y = mx + b

You might be interested in

A pyramid has a square base with side 9f lengths s. the height of the pyramid is equal to 1/2 of the lenght of a side on the bas

poizon [28]

Answer:

The formula would be A = 1/3(9)(9)(4.5) for an answer of 121.5

Step-by-step explanation:

To find this, start with the volume of a pyramid formula and inpout the known values.

A = 1/3lwh

A = 1/3(9)(9)(4.5)

A = 121.5

4 0

4 years ago

Answer this plz quickly

Arlecino [84]

Answer: THE ANSWER IS -1/36

Step by step: Find the LCD then combine

The answer is : -1/36

You forgot the 1 for 18 in the last question lol

Hope this helps, pls mark as brainliest :))))

3 0

4 years ago

You are going to take a 10-question True/False test. How many ways can this test be answered if leaving questions blank is a via

FinnZ [79.3K]

Answer:

2^10 = 1024

Step-by-step explanation:

The test most likely can be answered in two different ways. the different ways that 10 questions can be answered will be:

2^10 = 1024

6 0

3 years ago

What is the Y intercept? and where is the function positive?where is it negative?

kipiarov [429]

y=2

$\lbrack0,1)\text{ }\cup\text{ (3,4}\rbrack$

$\begin{gathered} so,\text{ the function is negative in } \\ (1,3) \end{gathered}$

Explanation

Step 1

The y -intercept of a graph is the point where the graph crosses the y -axis.

so , let's check the graph

therefore, the y-intercept is 2

Step 2

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero)

hence, the function is potive in ( in x axis)

$\lbrack0,1)\text{ }\cup\text{ (3,4}\rbrack$

Step 3

negative region

The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero).

$\begin{gathered} so,\text{ the function is negative in } \\ (1,3) \end{gathered}$

I hope this helps you

8 0

1 year ago

Please help me with this

Vlada [557]

what is the question?

8 0

4 years ago