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Lelu [443]
3 years ago
14

It's the holiday season and you are working for a packing company that specializes in holiday fruit cakes. For Christmas this ye

ar, the number of clients requesting fruit cakes has more than tripled and orders need to be shipped prior to the New Year. Your supervisor has asked you to work 15 hours more than a normal 40 hour work week, including Christmas day, which falls on a Friday. Therefore, one of your regular 8 hour days will be paid at the holiday rate. You get paid $10.00 per hour plus you get time and a half for overtime and double pay for the holidays. What will your gross base pay be for the week?
Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

$705

Step-by-step explanation:

Data

  • time worked on holiday: 8 hours
  • extra time worked: 15 hours
  • regular time worked: 40 - 8 = 32 hours
  • You get paid $10.00 per hour
  • double pay for the holidays.
  • time and half for overtime

Then:

Holiday payment = 2*10*8 = $160

Extra hours payment = 1.5*10*15 = $225

Regular time payment = 10*32 = $320

The gross base pay be for the week is $160 + $225 + $320 = $705

sasho [114]3 years ago
5 0
Your gross pay will be $705.

Here is the breakdown for your pay.

Regular: 32 x 10 = 320
Holiday: 8 x 20 = 160
Overtime: 15 x 15 = 225

If you add them all up, you get 705.
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Solve the differential equation dy/dx=x/49y. Find an implicit solution and put your answer in the following form: = constant. he
anygoal [31]

Answer:

The general solution of the differential equation is \frac{49y^{2} }{2}-\frac{x^{2} }{2} = c_{3}

The equation of the solution through the point (x,y)=(7,1) is y=\frac{x}{7}

The equation of the solution through the point (x,y)=(0,-3) is \:y=-\frac{\sqrt{441+x^2}}{7}

Step-by-step explanation:

This differential equation \frac{dy}{dx}=\frac{x}{49y} is a separable first-order differential equation.

We know this because a first order differential equation (ODE) y' =f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of <em>x</em> and <em>y</em>

f(x,y)=p(x)\cdot h(y) where<em> p(x) </em>and<em> h(y) </em>are continuous functions. And this ODE is equal to \frac{dy}{dx}=x\cdot \frac{1}{49y}

To solve this differential equation we rewrite in this form:

49y\cdot dy=x \cdot dx

And next we integrate both sides

\int\limits {49y} \, dy=\int\limits {x} \, dx

\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\\int\limits {49y} \, dy=\frac{49y^{2} }{2} + c_{1}

\int\limits {x} \, dx=\frac{x^{2} }{2} +c_{2}

So

\int\limits {49y} \, dy=\int\limits {x} \, dx\\\frac{49y^{2} }{2} + c_{1} =\frac{x^{2} }{2} +c_{2}

We can subtract constants c_{3}=c_{2}-c_{1}

\frac{49y^{2} }{2} =\frac{x^{2} }{2} +c_{3}

An explicit solution is any solution that is given in the form y=y(t). That means that the only place that y actually shows up is once on the left side and only raised to the first power.

An implicit solution is any solution of the form  f(x,y)=g(x,y) which means that y and x are mixed (<em>y</em> is not expressed in terms of <em>x</em> only).

The general solution of this differential equation is:

\frac{49y^{2} }{2}-\frac{x^{2} }{2} = c_{3}

  • To find the equation of the solution through the point (x,y)=(7,1)

We find the value of the c_{3} with the help of the point (x,y)=(7,1)

\frac{49*1^2\:}{2}-\frac{7^2\:}{2}\:=\:c_3\\c_3 = 0

Plug this into the general solution and then solve to get an explicit solution.

\frac{49y^2\:}{2}-\frac{x^2\:}{2}\:=\:0

\mathrm{Add\:}\frac{x^2}{2}\mathrm{\:to\:both\:sides}\\\frac{49y^2}{2}-\frac{x^2}{2}+\frac{x^2}{2}=0+\frac{x^2}{2}\\Simplify\\\frac{49y^2}{2}=\frac{x^2}{2}\\\mathrm{Multiply\:both\:sides\:by\:}2\\\frac{2\cdot \:49y^2}{2}=\frac{2x^2}{2}\\Simplify\\9y^2=x^2\\\mathrm{Divide\:both\:sides\:by\:}49\\\frac{49y^2}{49}=\frac{x^2}{49}\\Simplify\\y^2=\frac{x^2}{49}\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

y=\frac{x}{7},\:y=-\frac{x}{7}

We need to check the solutions by applying the initial conditions

With the first solution we get:

y=\frac{x}{7}=\\1=\frac{7}{7}\\1=1\\

With the second solution we get:

\:y=-\frac{x}{7}\\1=-\frac{7}{7}\\1\neq -1

Therefore the equation of the solution through the point (x,y)=(7,1) is y=\frac{x}{7}

  • To find the equation of the solution through the point (x,y)=(0,-3)

We find the value of the c_{3} with the help of the point (x,y)=(0,-3)

\frac{49*-3^2\:}{2}-\frac{0^2\:}{2}\:=\:c_3\\c_3 = \frac{441}{2}

Plug this into the general solution and then solve to get an explicit solution.

\frac{49y^2\:}{2}-\frac{x^2\:}{2}\:=\:\frac{441}{2}

y^2=\frac{441+x^2}{49}\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\y=\frac{\sqrt{441+x^2}}{7},\:y=-\frac{\sqrt{441+x^2}}{7}

We need to check the solutions by applying the initial conditions

With the first solution we get:

y=\frac{\sqrt{441+x^2}}{7}\\-3=\frac{\sqrt{441+0^2}}{7}\\-3\neq 3

With the second solution we get:

y=-\frac{\sqrt{441+x^2}}{7}\\-3=-\frac{\sqrt{441+0^2}}{7}\\-3=-3

Therefore the equation of the solution through the point (x,y)=(0,-3) is \:y=-\frac{\sqrt{441+x^2}}{7}

4 0
3 years ago
suppose the population of a town is growing exponentially. the population was 4,636 in 2008 and grew to 5,508 in 2018. what is t
Sloan [31]
<h2>94.93</h2>

Step-by-step explanation:

   The standard equation used to model a exponential growth is given by f(t)=Ae^{Bt}

   Given two data points, which are both explicitly a function of time, it is easy to solve the two equations,

4636=Ae^{2008B} ,5508=Ae^{2018B}

Dividing the second equation by the first,

\frac{5508}{4636}=\frac{Ae^{2018B} }{Ae^{2008B} }

e^{10B}=\frac{5508}{4636}

10B=ln(\frac{5508}{4636} )=0.17235

B=0.017235

Substituting in first equation, A=4.32645\textrm{x}10^{-12}

Growth model : f(t)=(4.3265\textrm{x}10^{-12} )e^{0.017235t}

Growth rate=ABe^{Bt}=94.93

∴Approximate growth rate as of 2018 = 95

5 0
3 years ago
Solve for x, then find the perimeter. You should select TWO answer choices.
dimulka [17.4K]

Answers:

x = 6 and P = 128

=================================================================

Explanation:

The tangents CT and CU are equal to each other. The rule is that tangent segments that meet at a common point are the same length.

Let's solve for x

CT = CU

3x = 18

x = 18/3

x = 6

Because CT = 18, this makes BC = BT+TC = 12+18 = 30

---------------------------

For similar reasoning as mentioned earlier, we can say tangents BT and BV are the same length. This means BV = 12.

Segment CD = 52 and CU = 18, which makes UD = CD-CU = 52-18 = 34

From there, we can say segment DV = 34 also. This leads to BD = BV+VD = 12+34 = 46

Triangle BCD has the three sides

  • BC = 30
  • CD = 52
  • BD = 46

The perimeter is

P = sum of the three sides

P = (side1)+(side2)+(side3)

P = BC + CD + BD

P = 30+52+46

P = 82+46

P = 128

7 0
3 years ago
Convert the following degrees into radians: 75°
ser-zykov [4K]

Answer:

1.309 I just I don't know

6 0
3 years ago
During the past school year, there were 640 students and 52 teachers. What is the ratio of students to each teacher rounded to t
Arisa [49]

Answer:

The ratio of student to teacher is 12.3 to 1

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