It’s 13 and 10. Since half of the product is 65 when it’s doubled you have 130, so basically you just to trial and error to get two numbers that add to 23 but multiple to get 130
Answer:
The answer to your question is
, because the directions says to give the answer in factor form.
Step-by-step explanation:

Factor like terms (x - 7)(x + 1)²

Simplify
![\frac{(x+1)^{2}[3(x - 7) - 2(x+1)]}{(x-7)^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%2B1%29%5E%7B2%7D%5B3%28x%20-%207%29%20-%202%28x%2B1%29%5D%7D%7B%28x-7%29%5E%7B3%7D%7D)
Expand
![\frac{(x+1)^{2}[3x - 21 -2x - 2]}{(x - 7)^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%2B1%29%5E%7B2%7D%5B3x%20-%2021%20-2x%20-%202%5D%7D%7B%28x%20-%207%29%5E%7B3%7D%7D)
Simplify
Answer:
So let the hypotenuse be
x
:
sin
(
47
°
)
=
opposite side
x
sin
(
47
°
)
=
12
x
To solve for
x
, divide
sin
(
47
°
)
by
12
:
x
=
12
sin
(
47
°
)
x
≈
16
Step-by-step explanation: