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MrRa [10]
3 years ago
11

Please please help me please help please please help me please help please

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

Perimeter is 17.07

Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

We need to use the Pythagorean theorem to get the length of DE.

DE = \sqrt{5^{2} +5^{2}}=\sqrt{50}  = 7.07\\

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07

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Calculate the rectangular prism with a length of 5.6cm, a with of 2.1 cm, and a height of 6.6cm.
Inessa05 [86]
5.6 x 2.1 x 6.6 = 77.616 2 significant figures would be 78 cm³ 2 decimal places would be 77.62 cm³
8 0
2 years ago
6. You begin work at 8:30 am. You take an unpaid lunch break from 11:45 am to 12:30 pm
STALIN [3.7K]

Answer:

7 hours 15 minutes

7.25 hours

Step-by-step explanation:

Break from 11:45 am to 12:30 pm = 45 minutes

Two 15-minute unpaid coffee breaks during the day = 30 minutes

Total break hours = 45 minutes + 30 minutes

= 1 hour 15 minutes

Total work day hours from 8:30 am to 5:00 pm = 8 hours 30 minutes

How many hours are you paid?

Total hours paid = Total work day hours - Total unpaid break hours

= 8 hours 30 minutes - 1 hour 15 minutes

= 7 hours 15 minutes

b) Express your answer as a decimal in hours only

7 hours 15 minutes as a decimal

15 minutes to hour = 60 minutes/15 minutes

= 1/4

= 0.25 hours

7 hours 15 minutes as a decimal = 7 hours + 0.25 hours

= 7.25 hours

7 0
2 years ago
Answer please........
Likurg_2 [28]

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4 0
3 years ago
Solve equation by using the quadratic formula.
Sati [7]

Answer: 1:  x=3, x=1

2:  x= -5

3:  There are 2 real solutions.

4:  There are 2 real solutions.

5:  There are no real solutions.

6.  There is 1 real solution.

7.  

8.  x= -6, x = -2

9.  x = -1/6, x=1

10.  

Explanation:

1.  The quadratic formula is

Substituting our known information we have:

2.  Rewriting the quadratic in standard form we have x²+10x-25=0. Substituting this into the quadratic formula gives us:

3.  The discriminant is b²-4ac.  For this problem, that is 20²-4(-4)(25)=400--400=800.  Since this is greater than 0, there are 2 real solutions.

4.  The discriminant in this problem is 7²-4(2)(-15)=49--120=49+120=169.  This is greater than 0, so there are 2 real solutions.

5.  The discriminant in this problem is 1²-4(-2)(-28)=1-224=-223.  Since this is less than 0, there are no real solutions.

6.  If the discriminant of a quadratic is 0, then by definition there is 1 real solution.

7.  Rewriting the quadratic we have 3x²-4x-2=0.  Using the quadratic formula we have:

8.  Factoring this trinomial we want factors of 12 that sum to 8.  6*2 = 12 and 6+2=8, so those are our factors.  This gives us:

(x+6)(x+2)=0

Using the zero product property we know that either x+6=0 or x+2=0.  Solving these equations we get x= -6 or x= -2.

9.  Factoring this trinomial we want factors of 6(-1)=-6 that sum to -5.  (-6)(1)=-6 and -6+1=-5, so this is how we "split up" the x term:

6x²-6x+1x-1=0

We group together the first two and the last two terms:

(6x²-6x)+(1x-1)=0

Factor the GCF out of each group.  In the first group, that is 6x:

6x(x-1)+(1x-1)=0

In the second group, the GCF is 1:

6x(x-1)+1(x-1)=0

Both terms have a factor of (x-1), so we can factor it out:

(x-1)(6x+1)=0

Using the zero product property, we know either x-1=0 or 6x+1=0.  Solving these equations we get x=1 or x=-1/6.

10.  Substituting our information into the quadratic formula we get:

Step-by-step explanation:

5 0
2 years ago
LM is a perpendicular bisector of NP The length of LN is 12w +7, and the length of LP is 15w 5. What is the length of LN?
Mazyrski [523]

Answer:

LN = 55

Step-by-step explanation:

Given

LN = 12w + 7

LP = 15w - 5

Required

Determine LN

Since LM is a bisector, then we have:

LP = LN (See attachment for illustration)

15w - 5 = 12w + 7

Collect Like Terms

15w - 12w = 5 +7

3w = 12

Solve for w

w = 12/3

w = 4

LN is calculated as thus:

LN = 12w + 7

Substitute 4 for w

LN = 12 * 4 + 7

LN = 48 + 7

LN = 55

8 0
2 years ago
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