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Galina-37 [17]
3 years ago
14

The table gives the values of a function obtained from an experiment. Use them to estimate 9 f(x) dx 3 using three equal subinte

rvals with right endpoints, left endpoints, and midpoints. x 3 4 5 6 7 8 9 f(x) −3.4 −2.2 −0.6 0.2 0.8 1.5 1.7
Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0
We shall use 3 equal subintervals, each with width = 2.

Integral with left end points:
A-left = -3.4*2 + (-0.6)*2 + 0.8*2 = -6.4

Integral with right end points:
A-right = -0.6*2 + 0.8*2 + 1.7*2 = 3.8

Integral with midpoints:
A-mid = -2.2*2 + 0.2*2 + 1.5*2 = -1.0

Notice that A-left < A-mid < A-right.
egoroff_w [7]3 years ago
3 0

Answer:

With right endpoints: -6.4

With left endpoints: 3.8

With midpoints: -1

Step-by-step explanation:

Given

x     3     4       5      6     7    8   9  

f(x) −3.4 −2.2 −0.6 0.2 0.8 1.5 1.7

We are asked to estimate the integral 3 to 9 f(x) dx.  

Using the intervals 3 to 5, 5 to 7 and 7 to 9, the length of the intervals is Δx = 2

With right endpoints the integral is:

f(3)*Δx + f(5)*Δx + f(7)*Δx  = (-3.4)*2 + (-0.6)*2 + 0.8*2 = -6.4

With left endpoints the integral is:  

f(5)*Δx + f(7)*Δx + f(9)*Δx  =  (-0.6)*2 + 0.8*2 + 1.7*2 = 3.8

With midpoint s the integral is:

f(4)*Δx + f(6)*Δx + f(8)*Δx = (-2.2)*2 + 0.2*2 + 1.5*2 = -1

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If we simply substitute the value x=2 in the expression we have

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f(x)=\dfrac{x^2-6x+8}{x^2-x-2} = \dfrac{(x-2)(x-4)}{(x+1)(x-2)}

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Answer:

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