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Diano4ka-milaya [45]
3 years ago
12

In a school of 145 students, each was asked to choose one or more activities from sport, music and drama.76 students choosr spor

t, 64 chose music and 40 students chose drama. 12 students chose both music and sport, 7 chose both sport and drama, and 21 chose both music and drama. How many students chose all three activities?​
Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

100 students chose all three

Step-by-step explanation:

first make a row for each subject and put how many students chose said subject. then subtract the number of students that chose both from the total amount of a subject

hope this helped

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lilavasa [31]

Answer:

18

Step-by-step explanation:  

subtract 32 and 14

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3 years ago
In 1950, scientist estimated a certain animal population in a particular geographical area to be 6400 in 2000, the population ha
irina1246 [14]

Answer:

8,100

Step-by-step explanation:

7,200 - 6,400 = 800 increased in 50. Years

What percentage is 800 of 6,400 (%/100 = is/of)

x/100 = 800/6400 (cross multiply)

(800*100)/6400 = 12.50%

(12.50 * 7200)/100 = 900 increased

7,200 + 900 = 8,100

7 0
2 years ago
Carly collected 4 1/4 pounds of newspaper for the recycling drive. Chloe collected 5 times as much newspaper as Carly. How many
BabaBlast [244]
The answer isss 21.25
7 0
3 years ago
Read 2 more answers
Find x and the perimeter of the triangle. <br><br> x= <br> perimeter=
agasfer [191]

Answer:

x = 10  Perimeter: 129

Step-by-step explanation:

FINDING X:

4x+7 = 5x -3

7 = x -3

10 = x

x = 10

PERIMETER:

4x + 7 + 5x - 3 + 4x - 5

Combine the "x" values

13x + 7- 3 - 5

Combine the numbers

13x - 1

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130 - 1

129

3 0
3 years ago
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The Internal Revenue Service (IRS) provides a toll-free help line for taxpayers to call in and get answers to questions as they
sukhopar [10]

Answer:

From the result of the one-tailed z-test, we can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Step-by-step explanation:

Sample size = 50

Mean waiting time = 13 minutes

Standard deviation = 11 minutes

We need to perform one hypothesis test that the actual mean waiting time turned out to be significantly less than the 15-minute claim made by the taxpayer advocate.

The null hypothesis would be that there is no significant difference.

H₀: μ₀ = 15 minutes

The alternative hypothesis would be that the mean waiting time is indeed significantly less than the 15-minute claim by the taxpayer advocate.

Hₐ: μ₀ < 15 minutes.

This is evidently a one tail hypothesis test (we're investigating only in one direction; less than the claim). Hence, we can use the z-test

z = (x - μ)/σₓ

σₓ = (σ/√n) = (11/√50) = 1.556

z = (13 - 15)/1.556 = - 1.29

Using the z-table at significance level of 0.05.

p-value = 1 - 0.9115 (from the z-tables)

p-value = 0.0885

Since the p-value is more than the significance level (0.0885 > 0.05), we do not reject the null hypothesis.

Hence, we accept the null hypothesis and can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Hope this Helps!!!

4 0
3 years ago
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