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NikAS [45]
3 years ago
14

The second term in a geometric sequence is 50. The fourth term in the same sequence is 112.5 . What is the common ration in this

sequence
Mathematics
1 answer:
ale4655 [162]3 years ago
7 0
Let the common ratio be r.
then 
a2*r*r=a4
rearrange,
r^2=a4/a2=112.5/50=2.25
r=sqrt(2.25)=1.5 = common ratio
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Adrian has a points card for a movie theater.
ANEK [815]

Answer: v ≥ 6

This means that Adrian needs to do at least 6 visits.

Step-by-step explanation:

First, we know that he gets 20 points just for signing up, so he starts with 20 points.

Now, if he makes v visits, knowing that he gets 2.5 points per visit, he will have a total of:

20 + 2.5*v

points.

And he needs to get at least 35 points, then the total number of points must be such that:

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and we know that:

points = 20 + 2.5*v

then we have the inequality:

20 + 2.5*v  ≥ 35

Now we can solve this for v, so we need to isolate v in one side of the equation:

2.5*v ≥ 35 - 20 = 15

2.5*v ≥ 15

v ≥ 15/2.5 = 6

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So he needs to make at least 6 visits.

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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2 years ago
Read 2 more answers
Am I dealing with harmonic stuff (trig)?
pochemuha

You just need to solve for when y=0:

\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0

\implies\cos8t=9\sin8t

\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t

\implies8t=\tan^{-1}\dfrac19+n\pi

\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8

where n is any integer. We only care about when 0\le t\le1, which happens for n\in\{0,1,2\}.

t=\dfrac18\tan^{-1}\dfrac19\approx0.01

t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41

t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80

8 0
3 years ago
Elliaarteaga14
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Answer:20 gallons

Step-by-step explanation:

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