The second term in a geometric sequence is 50. The fourth term in the same sequence is 112.5 . What is the common ration in this
1 answer:
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Order of operations
PEMDAS
parenthaseees
exponents
multiplication or division whichever comes first
addition or subtraction whichever comes first
parenthases first
inner to outer
left to right
treat a/b as (a)/(b) so simplify the fraction top and bottom as much as possible
the parenthaseese we have to simplify are
(20-5^2), (16+2^2), (3*2^2)
(20-5^2)
exponents first
5^2=25
now we have
(20-25)
subtract
20-25=-5
other parenthasees
16+2^2
exponent,
2^2=4
16+4=20
next
3*2^2
exponent
2^2=4
3*4=12
so the equaiton we have now is
exponents
-2^3 =-1 times 2^3
exponent first
2^3=8
-1 times 8=-8
now we hav
treat the numberator and denomenator as if they are in parenthasees so try to simplify them next
(-5)(20)=-100
-8+12=4
now we have
division
-100/4=-25
PEMDAS
parenthaseees
exponents
multiplication or division whichever comes first
addition or subtraction whichever comes first
parenthases first
inner to outer
left to right
treat a/b as (a)/(b) so simplify the fraction top and bottom as much as possible
the parenthaseese we have to simplify are
(20-5^2), (16+2^2), (3*2^2)
(20-5^2)
exponents first
5^2=25
now we have
(20-25)
subtract
20-25=-5
other parenthasees
16+2^2
exponent,
2^2=4
16+4=20
next
3*2^2
exponent
2^2=4
3*4=12
so the equaiton we have now is
exponents
-2^3 =-1 times 2^3
exponent first
2^3=8
-1 times 8=-8
now we hav
treat the numberator and denomenator as if they are in parenthasees so try to simplify them next
(-5)(20)=-100
-8+12=4
now we have
division
-100/4=-25
Answer:
3(x-2)+6=6x-9