Question

Write the equation in standard form for the circle with center (-7,0) and radius 3√3.

Answer 1

Answer: $(x +7)^2 + y^2 = 27$

Step-by-step explanation:

The standard form of a circle is written as such:

$(x - h)^2 + (y - k)^2 = r^2$

Where (h, k) is the center of the circle, and r is the radius.

We know that the center is (-7, 0), so we can plug that into the equation like this: $(x +7)^2 + y^2 = r^2$

The radius is 3 * the square root of 3. To square this, we can multiply 3 squared and the square root of 3 squared:

$3^2 * \sqrt{3} ^2 = 9 * 3$

So, your standard form equation is the following:

$(x +7)^2 + y^2 = 27$