HelpI don’t understand graphs and I will mark brainliest for the correct answer

Mathematics

1 answer:

qwelly [4]3 years ago

5 0

Answer:

G(x)=x^3-1

Step-by-step explanation:

Надеюсь тебе это поможет

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What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1?

JulsSmile [24]

Alright,
directix is y=something so it opens down or up

we use
(x-h)²=4p(y-k)
the vertex is (h,k)
and p is distance from focus to vertex
if focus is above directix, p is positive
if focus is below directix, p is negative

so we gts

focus=(1,1)
directix is y=-1
1>-1
focus is above

oh, vertex is in middle of focus and directix
so
beteeen (1,1) and y=-1 is, hmm
that is a distance of 2 vertically
2/2=1
1 down from (1,1) is (1,0)
vertex is (1,0)
p=1

so
(x-1)²=4(1)(y-0)
solving for y to get into f(x)=something form
(x-1)²=4y
y=1/4(x-1)²
f(x)=1/4(x-1)²

4th option

6 0

2 years ago

Simplify −4√−48<br> Help , please ?

Talja [164]

The answer is -16 radical 3

4 0

3 years ago

Make Q the subject of the formula A = Q2 - 2a.

son4ous [18]

Answer:

$\huge\boxed{Q = \sqrt{A+2a}}$

Step-by-step explanation:

$A = Q^2 -2a$

Adding 2a to both sides

$Q^2 = A+2a$

Taking sqrt on both sides

$Q = \sqrt{A+2a}$

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3 years ago

The functions f(x) = −(x − 1)2 5 and g(x) = (x 2)2 − 3 have been rewritten using the completing-the-square method. apply your kn

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The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.

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Given:

$\mathrm{f}(\mathrm{x})=-(\mathrm{x}-1)^{2}+5$ and