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3 years ago

Find the 76th term of the arithmetic sequence 16, 14, 12, ... I need help pls

Mathematics

2 answers:

Alona [7]3 years ago

6 0

Answer:

<h2>your answer is like this</h2>

Step-by-step explanation:

disa [49]3 years ago

5 0

Answer: The answer is -134

Step-by-step explanation: Common Difference:

d=a_2-a_1=(14)-(16)=-2d=a2−a1=(14)−(16)=−2

a_n=a_1+(n-1)dan=a1+(n−1)d

\text{76th term:}76th term:

a_{76}=16 + (76-1)(-2)a76=16+(76−1)(−2)

a_{76}=16 + (75)(-2)a76=16+(75)(−2)

a_{76}=-134a76=−134

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allochka39001 [22]

The water will last for 3 days

<em><u>Solution:</u></em>

Given that, village having a population of 4000, requires 150 litres of water per head per day

<em><u>Let us first find the volume of tank</u></em>

The tank measuring 20m x 15m x 6m

Length = 20 m

Breadth = 15 m

Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

Thus volume of tank is 1800 cubic meter

From given,

Water required per person per day = 150 liters

<em><u>Therefore, water required for 4000 people per day is:</u></em>

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

$600000 \text{ liters } = 600000 \times \frac{1}{1000}\ m^3\\\\600000 \text{ liters } = 600\ m^3$

<em><u>How many days will the water of this tank last?</u></em>

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

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3 years ago