Find the 76th term of the arithmetic sequence 16, 14, 12, ...
I need help pls
2 answers:
Answer:
<h2>your answer is like this</h2>
Step-by-step explanation:
<h2>a)16. d)-2</h2><h2>an=a+(n-1)d</h2><h2>a76=16+(76-1)-2</h2><h2>=16-150</h2><h2>=-136</h2>
Answer: The answer is -134
Step-by-step explanation: Common Difference:
d=a_2-a_1=(14)-(16)=-2d=a2−a1=(14)−(16)=−2
a_n=a_1+(n-1)dan=a1+(n−1)d
\text{76th term:}76th term:
a_{76}=16 + (76-1)(-2)a76=16+(76−1)(−2)
a_{76}=16 + (75)(-2)a76=16+(75)(−2)
a_{76}=-134a76=−134
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Step-by-step explanation:
You can do this by completing the square on x and y terms:
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Answer:
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Step-by-step explanation: if your finding the decimal 2.3 will be your answer if not then sorry
Answer:
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Step-by-step explanation:
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